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3 years ago

X² + 15x + 14 Solve this please

Mathematics

2 answers:

Yuri [45]3 years ago

6 0

Answer:

(x+14)·(x+1)

Step-by-step explanation:

I just put the equation on Photomath....

Orlov [11]3 years ago

3 0

Answer:

x=14

x=1

Step-by-step explanation:

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Using the distributive property to find the product (y−4x)(y2+4y+16) results in a polynomial of the form y3+4y2+ay−4xy2−axy−64x.

Viefleur [7K]

Answer:

Step-by-step explanation:

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4 years ago

Read 2 more answers

A recipe calls for 1/4 cup of brown sugar for every 2/3 cup of white sugar. How many cups of brown sugar is required for every c

sammy [17]

The right answer is Option B: 3/8

Step-by-step explanation:

Given,

1/4 cup of brown sugar is for 2/3 cup of white sugar.

Ratio of brown sugar to white sugar = $\frac{1}{4}:\frac{2}{3}$

Let,

x be the brown sugar required for 1 cup of white sugar.

Ratio of brown sugar to white sugar = x:1

Using proportion;

Ratio of brown sugar to white sugar :: Ratio of brown sugar to white sugar

$\frac{1}{4}:\frac{2}{3}::x:1$

Product of mean = Product of extreme

$\frac{2}{3}*x=\frac{1}{4}*1\\\frac{2}{3}x=\frac{1}{4}$

Multiplying both sides by 3/2

$\frac{3}{2}*\frac{2}{3}x=\frac{1}{4}*\frac{3}{2}\\x=\frac{3}{8}$

3/8 cups of brown sugar is required for 1 cup of white sugar.

The right answer is Option B: 3/8

Keywords: ratio, proportion

Learn more about ratios at:

#LearnwithBrainly

3 0

3 years ago

Suppose that only 20% of all drivers come to a complete stop at an intersection having flashing red lights in all directions whe

Lina20 [59]

Answer:

a) 91.33% probability that at most 6 will come to a complete stop

b) 10.91% probability that exactly 6 will come to a complete stop.

c) 19.58% probability that at least 6 will come to a complete stop

d) 4 of the next 20 drivers do you expect to come to a complete stop

Step-by-step explanation:

For each driver, there are only two possible outcomes. Either they will come to a complete stop, or they will not. The probability of a driver coming to a complete stop is independent of other drivers. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

20% of all drivers come to a complete stop at an intersection having flashing red lights in all directions when no other cars are visible.

This means that $p = 0.2$

20 drivers

This means that $n = 20$

a. at most 6 will come to a complete stop?

$P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{20,0}.(0.2)^{0}.(0.8)^{20} = 0.0115$

$P(X = 1) = C_{20,1}.(0.2)^{1}.(0.8)^{19} = 0.0576$

$P(X = 2) = C_{20,2}.(0.2)^{2}.(0.8)^{18} = 0.1369$

$P(X = 3) = C_{20,3}.(0.2)^{3}.(0.8)^{17} = 0.2054$

$P(X = 4) = C_{20,4}.(0.2)^{4}.(0.8)^{16} = 0.2182$

$P(X = 5) = C_{20,5}.(0.2)^{5}.(0.8)^{15} = 0.1746$

$P(X = 6) = C_{20,6}.(0.2)^{6}.(0.8)^{14} = 0.1091$

$P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.0115 + 0.0576 + 0.1369 + 0.2054 + 0.2182 + 0.1746 + 0.1091 = 0.9133$