Answer:
4.56
Step-by-step explanation:
i see a sector hosting 2 semi circles.
this sector area will be .25 of area of circle with radius 4ft.
area of sector = .25*π*16= 4π ft^2
area of semi circle of radius 2ft = .5π*4= 2πft^2
area of 2 semicircles = 4π
the total area of sector = area of 2 semicircles - intersection area + area not covered by semi circles
4π = 4π - intersection area+area not covered by semi circles
intersection area = area not covered by semi circles
now draw a square starting from the intersection point of 2 semi circles at their upper portion. the side will be 2ft
the area of intersection will be covered in the square.
area of intersection = 2*quarter area of circle of radius 2ft - area of square
= 2*(.25π4) - 4
2π-4 = 2.28
area of intersection = area not covered by semicircle
so area of shaded region = 4.56
12. 1.625 [terminating]; 13. 0.83 [bar notation over 3 (repeating)]; 14. 900 cm = 9 m; 15. 0.23 cm = 2.3 mm
Repeating decimals are parts of decimals that have repetitive digits; terminating decimals are decimals whose digits end.
Whether you are using Metric or Imperial, you have to determine whether you are going from a small unit to a big unit or vice versa. Then perform your operation. So, in exercise 14, the smaller unit is centimeters, so you would be going from big to small. Exercise 15 has you going from small to big.
There are centimeters in one meter, so multiply 9 by to get 900 centimeters.
There are 10 millimeters in one centimeter, so divide 2.3 by 10 simply by moving the decimal point ONCE to the left [Power of 10].
small to BIG → Division
BIG to small → Multiplication
I am joyous to assist you anytime.
I believe 8 is the answer