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arlik [135]
3 years ago
11

Look at the figures. How can you prove the triangles are congruent?

Mathematics
1 answer:
alexira [117]3 years ago
3 0
The figures are no congruent perioddddt
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Pls help duhdiudhuod
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Answer:

X. y

10. $7

24. $14

38. $ 21

6 0
3 years ago
Simplify completely (h^12 /h^4) ^3
Svetach [21]

Answer:

h^24

Step-by-step explanation:

h^12 divided by h^4 is h^8 according to the rule of exponent because if you divide the two terms that have the same base but different exponents, you have to subtract the exponent number. 12-4=8.

(h^8)^3 is h^24 because again according to the rule of exponent you have to multiply the two exponents together, and 8 * 3 is 24.

The simplified expression is h^24.

8 0
4 years ago
Please help soon!
Jlenok [28]

Answer:

a) Translate the graph of f(x) down 3 units.

b) (8,-1) is a point on the graph of g(x)

Step-by-step explanation:

The transformations that subtract a constant number of units from the functional expression f(x) are transformations that lower the graph of the function in those many units,

Therefore they correspond to a translation of the original graph down the number of units involved.

In this case, the number of units involved is "3" (due to the "-3" added to the expression for f(x). So he correct answer for the first part is: Translate the graph of f(x) down 3 units.

For the second part, one has to try each of the coordinate pairs given in the new function g(x) to see which one results in a true statement:

1) Testing (-8,-1) by checking if replacing x with the value "-8" renders "-1" for the y-value: g(x)=\sqrt[3]{x} -3\\g(-8)=\sqrt[3]{-8} -3\\g(-8)=-2-3\\g(-8)=-5

so this is NOT a point on the graph of g(x).

2) Testing (-1,-2) by checking if replacing x with the value "-1" renders "-2" for the y-value: g(x)=\sqrt[3]{x} -3\\g(-1)=\sqrt[3]{-1} -3\\g(-1)=-1-3\\g(-1)=-4

so this is NOT a point on the graph of g(x).

3) Testing (2,-1) by checking if replacing x with the value "2" renders "-1" for the y-value: g(x)=\sqrt[3]{x} -3\\g(2)=\sqrt[3]{2} -3\\

the cubic root of 2 is not a rational number, because 2 is not a perfect cube, so the expression cannot be reduced, so this is NOT a point on the graph of g(x).

4) Testing (8,-1) by checking if replacing x with the value "8" renders "-1" for the y-value: g(x)=\sqrt[3]{x} -3\\g(8)=\sqrt[3]{8} -3\\g(8)=2-3\\g(8)=-1

Therefore this pair (8,-1) IS a point on the graph of g(x).

5 0
3 years ago
Read 2 more answers
Các mô hình h i quy sau đây có ph i mô hình tuy n tính hay không? N u là môồảếếhình h i quy phi tuy n, hãy đ i v mô hình h i quy
valina [46]
Yes! This work is all correct.
4 0
3 years ago
60,000 is one tenth of
Tatiana [17]
600,000 u just have to multiply it by 10

4 0
4 years ago
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