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kaheart [24]
2 years ago
15

What is the surface area of this shape? 1 cm 5 cm 4 cm 2 cm 6 cm 3 cm

Mathematics
1 answer:
djyliett [7]2 years ago
3 0
I don’t know I think it’s 6cm
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Use Cramer's Rule to solve each system.<br> 5x – 3y = 8<br> -2x - y = 10
zlopas [31]

Answer:

-2, -6

Step-by-step explanation:

using cramer rule

5    -3    

-2   -1    

calculatiing the determinant = (5 x-1) - (-3x-2) = -5 -(6) = -5-6=-11

using cramer rule

to calculate x we change the coefficient of x with the answer (8,10)

8   -3

10   -1

we calculate determinant = (8x-1)-(-3x10) = -8-(-30) = -8+30 =22

to calculate x

22/-11= -2

to calculate y we change the coefficient of y with the answer (8,10)

5   8

-2   10

we calculate determinant = (5x10)-(8x-2) = 50 -(-16) = 50 +16=66

to calculate y

66/-11= -6

6 0
3 years ago
Read 2 more answers
What’s the mean of 3,9,10,14,15,16
Ostrovityanka [42]
I think it might be 11.1
4 0
3 years ago
Read 2 more answers
Write an equation in general form for the line passing through (-12,-1) and perpendicular to the line whose equation is 6x-y-4=0
Rus_ich [418]

The Solution:

Given the equation of a line:

6x-y-4=0

We are required to find the equation of a line that is perpendicular to the given line and passes through the point (-12,-1).

Step 1:

Determine the slope of 6x-y-4=0.

\begin{gathered} \text{  Express y in terms of x.} \\ 6x-4=y \\ y=6x-4 \end{gathered}

The coefficient x, after making y the subject of the formula, is the slope of the given line. That is:

\begin{gathered} \text{ The slope of }6x-y-4=0\text{ is 6} \\  \\ Slope=m_1=6 \end{gathered}

Step 2:

Find the slope of the required line:

Since the two lines are perpendicular, the slope is:

\begin{gathered} m_2=\frac{-1}{m_1}=\frac{-1}{6} \\  \end{gathered}

Step 3:

Find the equation of the line that passes through point (-12,-1)

By formula,

y-y_1=m_2(x-x_1)

In this case,

\begin{gathered} x_1=-12 \\ y_1=-1 \end{gathered}

Substituting these values in the formula, we get the required equation is:

\begin{gathered} y--1=\frac{-1}{6}(x--12) \\  \\ y+1=-\frac{1}{6}(x+12) \end{gathered}

Cross multiplying, we get

\begin{gathered} 6y+6=-x-12 \\  \\ 6y+x+6+12=0 \\  \\ 6y+x+18=0 \end{gathered}

Therefore, the correct answer is:

6y+x+18=0

5 0
1 year ago
7z+15+27, z, plus, 15, plus, 2
ANEK [815]

Answer:

7z + 15 + 27 \\ 7z + 42 \\ z = 42 \div 7 \\ z = 6

7 0
3 years ago
How do i create a predictable sequence of at least 4 numbers that is NOT arithmetic or geometric?
g100num [7]
Numbers that are already in order are predictable.
Example:1,2,3,4
3 0
3 years ago
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