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3 years ago

8

the number of calories in a container of milk is directly proportional to the amount of milk in the container. if there are 160

calories in an 8-ounce glass of milk, find the number of calories in a 15-ounce of milk?

1 answer:

lorasvet [3.4K]3 years ago

6 0

Answer:

300

Step-by-step explanation:

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OlgaM077 [116]

7. (150 cal)/(3/4 serving) = 150/1 / 3/4 = 150/1 * 4/3 = 200 cal/serving

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A particle is moving along the parabola x^2=4(y+6). As the particle passes through the point (8,10), the rate of change of its y

Fofino [41]

You'll need to use differentiation (specifically, implicit differentiation) here.

If x^2 = 4(y+6), differentiating both sides with respect to time t produces the following:

2x (dx/dt) = 4([dy/dt]) (note that (d/dt) 6 = 0)

We need to solve for (dx/dt). Substitute 8 for x (y does not appear in this latest equation, so we do nothing with y=10). Substitute the given 5 units/sec for dy/dt:

2(8)(dx/dt) = 4(5)(units/sec)

Solving for dx/dt, dx/dt = [20 units/sec]/16, or 5/4 units/sec, or 1.25 units/sec.

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Valentin [98]

Answer:

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Step-by-step explanation:

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Question:2x²-5x+3 <br>answer:

masya89 [10]

(x-1)(2x-3) OR x= 3/2, 1

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lim x rightarrow 0 1 - cos ( x2 ) / 1 - cosx The limit has to be evaluated without using l'Hospital'sRule.

zaharov [31]

Answer with Step-by-step explanation:

Given

$f(x)=\frac{1-cos(2x)}{1-cos(x)}\\\\\lim_{x \rightarrow 0}f(x)=\lim_{x\rightarrow 0}(\frac{1-(cos^2{x}-sin^2{x})}{1-cos(x)})\\\\(\because cos(2x)=cos^2x-sin^2x)\\\\\lim_{x \rightarrow 0}f(x)=\lim_{x\rightarrow 0}(\frac{1-cos^2x}{1-cos(x)}+\frac{sin^2x}{1-cosx})\\\\=\lim_{x\rightarrow 0}(\frac{(1-cosx)(1+cosx)}{1-cosx}+\frac{sin^2x}{1-cosx})\\\\=\lim_{x\rightarrow 0}((1+cosx)+\frac{sin^2x}{1-cosx})\\\\\therefore \lim_{x \rightarrow 0}f(x)=1$

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3 years ago