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Airida [17]
3 years ago
14

Please help! Thank you! Also, please explain thank you!

Mathematics
1 answer:
viva [34]3 years ago
5 0

Answer:

2x=10*11

2x=110

so

x=55

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What are all of the real roots of the following polynomial? f(x) = x5 + 5x4 - 5x3 - 25x2 + 4x + 20
Nadusha1986 [10]
F(x)=x^5 + 5*x^4 - 5*x^3 - 25*x^2 + 4*x + 20

By examining the coefficients of the polynomial, we find that
1+5-5-25+4+20=0 => (x-1) is a factor
Now, reverse the sign of coefficients of odd powers,
-1+5+5-25-4+20=0 => (x+1) is a factor

By the rational roots theorem, we can continue to try x=2, or factor x-2=0
2^5+5(2^4)-5(2^3)-25(2^2)+4(2)+20=0
and similarly f(-2)=0
So we have found four of the 5 real roots.
The remainder can be found by synthetic division as x=-5


Answer: The real roots of the given polynomial are: {-5,-2,-1.1.2}

8 0
3 years ago
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64% of x is 140 please help me right away and solve me x!
nata0808 [166]

Answer:

218.75

Step-by-step explanation:

218.75

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4 0
3 years ago
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I got a question sooo​
AlladinOne [14]

Answer:

5x +2=17

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6 0
3 years ago
Can I get help on this please someone
Aleonysh [2.5K]

Answer:

C

Step-by-step explanation:

Let's break down the definitions.

Supplementary = degrees add up to 180

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Complementary = degrees add up to 90

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Since the degrees add up to 90 and don't share a common side/vertex, the angles are complementary.

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Question 6 Multiple Choice Worth 1 points)
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Answer:

Step-by-step explanation:

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3 years ago
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