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kherson [118]
3 years ago
5

Please help! Brainliest !

Mathematics
1 answer:
BartSMP [9]3 years ago
8 0
The answer is c Bc it’s bigger than what it’s talking about
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Find the coordinates of the other endpoint of the​ segment, given its midpoint and one endpoint.​ (Hint: Let​ (x,y) be the unkno
makkiz [27]

Step-by-step explanation:

Hey, there!!

Here, one point is A(10,8) and P(8,5) is the midpoint.

Let B(x,y) be the another end point.

Now,

Using midpoint formulae,

p(x.y) =  \frac{x1 + x2}{2} . \frac{y1 + y2}{2}

p(8.5) = ( \frac{10 + x}{2} . \frac{8 + y}{2} )

Since they are equal,equating with their corresponding elements we get,

8 =  \frac{10 + x}{2}

or, 16 = 10 + x

or, x=16-10

Therefore, x = 6

Now,

5 =  \frac{8 + y}{2}

or, 10 = 8 + y

or, y = 2

Therefore, The coordinates of another point are B(6,2)

<em><u>Hope it helps</u></em><em><u> </u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

8 0
4 years ago
Which can be used to find the distance between points at (-5,-12) and (-5,14)?
GREYUIT [131]
Pythagorean Theorem as follows: A^2+B^2=C^2
6 0
4 years ago
Four friends go to the movies and pay $11 per ticket. They also each buy a snack
Setler79 [48]

Answer:

Each snack combo costed $8

Step-by-step explanation:

4 friends* 11 per ticket = $44 for four tickets

76 - 44 = $32 spent on all the snack combos

$32 ÷ 4 friends = $8 spent on each snack combo

So, each snack combo costed $8

Hope this helps!

6 0
2 years ago
Read 2 more answers
Help solve 4 and 5 please
Sloan [31]

Answer:

Step-by-step explanation:

4). a). If the diagonals of a parallelogram are congruent, then it must be a RECTANGLE.

b). If the diagonals of a parallelogram are perpendicular, then it must be a SQUARE.

c). If the diagonals of a parallelogram bisect the angles of the parallelogram, then it must be a RHOMBUS.

d). If the diagonals of a parallelogram are perpendicular and congruent, then it must be a SQUARE.

e). If a parallelogram has four congruent sides, then it must be a SQUARE.

5). Given quadrilateral SELF is a rhombus.

a). All sides of a rhombus are equal,

   Therefore, ES = EL = 25

b). Diagonals of a rhombus bisects the opposite angles,

   Therefore, m∠ELS = m∠FLS

    3x - 2 = 2x + 7

    3x - 2x = 7 + 2

    x = 9

c). Diagonals of the rhombus bisect the opposite angles, and adjacent angles are supplementary.

m∠ELF = 2(m∠ELS) = 2(2y - 9)

m∠LES = 2(m∠LEF) = 2(3y + 9)

And 2(2y - 9) + 2(3y + 9) = 180

(2y - 9) + (3y + 9) = 90

5y = 90

y = 18  

6 0
3 years ago
The greatest common factor of 3m^2n+12mn^2 is
FromTheMoon [43]
3m^2n=3mn\cdot m\\\\12mn^2=3mn\cdot4n\\\\GCF(3m^2n;\ 12mn^2)=3mn\\\\3m^2n+12mn^2=3mn(m+4n)
6 0
4 years ago
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