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Kobotan [32]
3 years ago
6

The community center provides tutoring for students p. The cost of the tutoring is $18 per session. Write an equation to model t

he total cost (c), after (s) sessions
A) c=18s
B) c= 18+s
C) c= s-18
D) s=18c

Pls hurry
Mathematics
2 answers:
miv72 [106K]3 years ago
4 0

Answer: A) c=18s

Step-by-step explanation: Each session means we are multiplying so we can eliminate B and C so next we must understand where to place our variables. If it is 18 per session then 18s would be the equation and equal the total cost (c) soo the answer is c=18s

Viefleur [7K]3 years ago
4 0
answer: C. c= s-18
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PLSSS HELP IF YOU TURLY KNOW
mylen [45]

Answer:

x = 5

Step-by-step explanation:

(3-6x)/3 = -11

first multiple both sides by 3

3 - 6x = -33

then subtract 3 from both sides

-6x = -30

then divide by 6

x = 5

8 0
2 years ago
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Find the area of the region under the graph of f on [a, b].<br> f(x) = x2 − 8x + 17; [−1, 2]
Harman [31]

Answer:

The area is 42 area units.

Step-by-step explanation:

The area of a function f(x) on an interval [a,b] is given by:

A = \int\limits^a_b {f(x)} \, dx

Applying to this question:

A = \int\limits^-1_2 {x^2 - 8x + 17} \, dx

Then

F(x) = \frac{x^{3}}{3} - 4x^{2} + 17x

A = F(2) - F(-1)

F(2) = frac{2^{3}}{3} - 4*2^{2} + 17*2 = \frac{8}{3} + 18 = \frac{8 + 3*18}{3} = \frac{62}[3}

F(-1) = frac{(-1)^{3}}{3} - 4*(-1)^{2} + 17*(-1) = -\frac{1}{3} - 21 = \frac{-1 - 21*3}{3} = -\frac{64}[3}

A = F(2) - F(-1) = \frac{62}[3} - (-\frac{64}[3}) = \frac{62+64}{3} = 42

The area is 42 area units.

5 0
3 years ago
Find the following GCD and LCM: (3.a) GCD(343,550), LCM(343, 550). (3.b) GCD(89, 110), LCM(89, 110). (3.c) GCD(870, 222), LCM(87
Ierofanga [76]

Answer with Step-by-step explanation:

(3.a) GCD(343,550), LCM(343, 550).

343=7×7×7

550=5×5×2×11

GCD(343,550)=1

LCM(343,550)=7×7×7×5×5×2×11=188650

(3.b) GCD(89, 110), LCM(89, 110).

89=1×89

110=5×2×11

GCD(89, 110)=1

LCM(89, 110)=89×5×2×11=9790

(3.c) GCD(870, 222), LCM(870, 222).

870=2×3×5×29

222=2×3×37

GCD(870, 222)=2×3=6

LCM(870, 222)=2×3×5×29×37=32190

5 0
3 years ago
If a ball is thrown into the air with a velocity of 48 ft/s, its height in feet t seconds later is given by y = 48t − 16t2. Find
dimaraw [331]
The formula for average velocity between two times t1 and t2 of the position function f(x) is (f(t2)-f(t1)) / (t2-t1)
Plugging the values in for the first time period we get (f(2.5)-f(2)) / (2.5-2)
=> (f(2.5)-f(2)) / 0.5
f(2) will be the same for all 4 time periods and is
48(2)-16(2)^2 = 32
Now we plugin the other values
f(2.5) = 48(2.5)-16(2.5)^2 = 20
f(2.1) = 48(2.1)-16(2.1)^2 = 30.25
etc.
f(2.05) = 31.16
f(2.01) = 31.8384
Now plug these values into the formula
(20-32)/0.5 = -24
(30.25-32)/0.1 = -17.5
etc.
= -16.8
= -16.16
Final answer:
2.5s => -24 ft/s
2.1s => -17.5 ft/s
2.05 => -16.8 ft/s
2.01 => -16.16 ft/s
Hope I helped :)
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2 years ago
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Fed [463]

Answer:

-7/9

Step-by-step explanation:

here you go I hope it helps

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