Temperature rose 9°f in 3 hours if the starting wad -5°f what was the final temperature

Identify the volume of the composite figure rounded to the nearest tenth. HELP PLEASE!!

nirvana33 [79]

Answer:

V = 115.3 ft³

Step-by-step explanation:

The left part of the figure shows a cube of side length 4.2 ft. The volume of a cube is V = s³, where s is the side length. Hence, the volume of this particular cube is V = (4.2 ft)³ = 74.088.

The volume of a pyramid is V = (1/3)(base area)(height).

Here V = (1/3)(4.2 ft)²(7 ft) = 41.16 ft³.

Summing up the two distinct areas, we get V = 41.16 ft³ + 74.088 ft³, or

V = 115.3 ft³ after rounding up to the nearest tenth.

3 0

2 years ago

Find the P-value for the indicated hypothesis test with the given standardized test statistic, z. Decide whether to reject H0

Leviafan [203]

Answer: We do not reject the null hypothesis.

Step-by-step explanation:

When the p-value is greater than the significance level , then we do not reject the null hypothesis or if p-value is smaller than the significance level , then we reject the null hypothesis.

Given : Test statistic : $z = -2.28$

Significance level : $\alpha=0.02$

By using the standard normal distribution table ,

The p-value corresponds to the given test statistic ( two tailed ):-

$2P(Z>|z|)=2P(Z>2.28)=0.0226$

Since the p-value is greater than the significance level of 0.02.

Then , we do not reject the null hypothesis.

8 0

3 years ago

Find mCE A. 40 DEGREES B. 50 DEGREES C. 75 DEGREES D. 80 DEGREES

nordsb [41]

B. 50 degrees hope this helps

3 0

2 years ago

A population has a standard deviation of 5.5. What is the standard error of the sampling distribution if the sample size is 81?

VladimirAG [237]

Answer:

$\sigma = 5.5$

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution $\bar X$ and for this case we know that the distribution is given by:

$\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611$

Step-by-step explanation:

For this case we know the population deviation given by:

$\sigma = 5.5$

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution $\bar X$ and for this case we know that the distribution is given by:

$\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611$

4 0

2 years ago

NEED THE CORRECT ANSWER ASAP, PLEASE HELP!!! Drag and drop the expressions into the boxes to correctly complete the proof of the

belka [17]

Answer:

See attached

Step-by-step explanation:

The proof is attached

4 0

3 years ago