Answer:
Option d :18 bags of chips and 6 jars of salsa
Step-by-step explanation:
Given : The networking organization you joined is throwing a party. You are in charge of buying the chips, which cost $2.50 per bag and salsa, which costs $4 per jar. The chips & salsa budget you are given totals $60.
Inequality : ![2.5x+4y\leq 60](https://tex.z-dn.net/?f=2.5x%2B4y%5Cleq%2060)
Solution :
x represents chips
y represents salsa
Option a: 10 bags of chips and 2 jars of salsa
so, x = 10 and y =2
Putting values in inequality
![2.5(10)+4(2)\leq 60](https://tex.z-dn.net/?f=2.5%2810%29%2B4%282%29%5Cleq%2060)
![25+8\leq 60](https://tex.z-dn.net/?f=25%2B8%5Cleq%2060)
![33\leq 60](https://tex.z-dn.net/?f=33%5Cleq%2060)
Hence it is correct.
Option b : 20 bags of chips and 2 jars of salsa
so, x = 20 and y =2
Putting values in inequality
![2.5(20)+4(2)\leq 60](https://tex.z-dn.net/?f=2.5%2820%29%2B4%282%29%5Cleq%2060)
![50+8\leq 60](https://tex.z-dn.net/?f=50%2B8%5Cleq%2060)
![58\leq 60](https://tex.z-dn.net/?f=58%5Cleq%2060)
Hence it is correct.
Option c : 14 bags of chips and 5 jars of salsa
so, x = 14 and y =5
Putting values in inequality
![2.5(14)+4(5)\leq 60](https://tex.z-dn.net/?f=2.5%2814%29%2B4%285%29%5Cleq%2060)
![35+20\leq 60](https://tex.z-dn.net/?f=35%2B20%5Cleq%2060)
![55\leq 60](https://tex.z-dn.net/?f=55%5Cleq%2060)
Hence it is correct.
Option d :18 bags of chips and 6 jars of salsa
so, x = 18 and y =6
Putting values in inequality
![2.5(18)+4(6)\leq 60](https://tex.z-dn.net/?f=2.5%2818%29%2B4%286%29%5Cleq%2060)
![45+24\leq 60](https://tex.z-dn.net/?f=45%2B24%5Cleq%2060)
![69\geq 60](https://tex.z-dn.net/?f=69%5Cgeq%2060)
Hence it is not correct since it violates the inequality
Answer:
14/3 or 4 2/3
Step-by-step explanation:
Hope it helps :)
Brainliest pls? Have a good day/night
Answer:
368 sq. units.
Step-by-step explanation:
We have a square of side lengths 20 units and we cut four congruent isosceles right triangles from the corners of the square.
Now, the four isosceles right triangles have one leg equal to 4 units.
Therefore, the area of four triangles =
sq. units.
Now, we have the area of the given square is (20 × 20) = 400 sq. units.
Therefore, the area of the remaining octagon will be (400 - 32) = 368 sq. units. (Answer)
5∛x + 4 = 44
5∛x = 40
∛x = 8
x = 8^3
x = 512
answer
C. 512