Answer:
a) 32
b) 67.613
Step-by-step explanation:
<em><u> In Game 3, Emerson struck out 42 times in 140 times at-bat.</u></em>
<em><u>Part A</u></em>
<em><u>Drag numbers to complete the proportion to represent the percent of strikeouts per at-bats.</u></em>
<em><u>Numbers may be used once or not at all.</u></em>
<em><u /></em>
<em><u>Part B</u></em>
<em><u>What percentage of times at bat did Emerson actually hit the ball?</u></em>
Part A
Total number of strikeouts= 30+40+42= 112
Total number of at bats = 90+120+140= 350
strikeouts : times
112: 350
p:100
Using cross product rule
p/100= 112/350
p * 350= 112*100
or p= 11200/350= 32
It means that there were 32 strikeouts if 100 times were bat at hits.
Part B:
Total number of strikeouts= 30+40+42= 112
Total number of at bats = 90+120+140= 350
But we need the percentage of times at bat hit
Therefore
Hits= times - strikeouts= 350-112= 238
Percentage = 238/352*100= 67.613
Check
The above answers are correct because
100-32 = 68
68 ≅ 67.613
Answer:
????? what?
Step-by-step explanation:
Answer:
y = 6x+8
Step-by-step explanation:
y = mx+b
y = 6x + b
2 = 6(-1)+b
2 = -6+b
8 = b
y = 6x+8
Answer:
A
Step-by-step explanation:
Answer:
Sh. 9000
Step-by-step explanation:
John : Peter = 2 : 1
John/peter = 2/1
John = 2 Peter.... (1)
Amos : John = 4:3
Amos/John = 4/3
Amos = 4/3 John.. (2)
From (1) & (2)
Amos = 4/3 * 2 Peter = 8/3 Peter.... (3)
Since,
Amos + John + Peter = 51000
Therefore,
8/3 Peter + 2peter + Peter = 51000
(8+6+3)/3 *Peter = 51000
17/3 * Peter = 51000
Peter = 51000 * 3/17
Peter = 3000 * 3
Peter = 9000
Hence, amount received by Peter is Sh. 9000.