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nignag [31]
2 years ago
5

Make predictions using experimental probability can someone explain this topic please

Mathematics
1 answer:
Gekata [30.6K]2 years ago
3 0

You should multiply the experimental probability by the total number of trials in an actual experiment when making a prediction.

<h3>What is an experimental probability?</h3>

An experimental probability is also referred to as relative frequency or empirical probability and it can be defined as a ratio of the number of outcomes for the occurrence of a specific event to the total number of trials in an actual experiment.

In order to make a prediction by using experimental probability, you should multiply the experimental probability by the total number of trials in an actual experiment.

Read more on experimental probability here: brainly.com/question/10128393

#SPJ1

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Reduce to simplest form. <br> -7/12 +3/8
gayaneshka [121]

Answer:

ok so you should get -5/24 in simplest form.

Decimal form- -0.2083 repeating

Step-by-step explanation:

Hope this helped :)

4 0
3 years ago
In parallelogramMNOP , PK=5x and KN=x2−14 . What is PN ?<br><br>73670100
lisov135 [29]
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4 years ago
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In a large apartment building, 35 of the apartments have a balcony and 55 do not.
Masteriza [31]
Hello!

You first have to find the total amount of apartments

35 + 55 = 90

There are 90 apartments

Then you find the percentage of them have a balcony

You do this by taking the amount of apartments that have a balcony over the total amount of apartments

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The answer is 39/100 or 39%

Hope this helps!
5 0
3 years ago
Choose all of the functions that are linear.
xxTIMURxx [149]

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5 0
2 years ago
Simplify.<br><br> 1/4 (1 - 2/3)² + 1/3.<br><br> The answer must be a simplified fraction.
loris [4]

Answer:

\large\boxed{\dfrac{13}{36}}

Step-by-step explanation:

Use PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

---------------------------------------------------------------------------

\dfrac{1}{4}\left(1-\dfrac{2}{3}\right)^2+\dfrac{1}{3}=\dfrac{1}{4}\left(\dfrac{3}{3}-\dfrac{2}{3}\right)^2+\dfrac{1}{3}=\dfrac{1}{4}\left(\dfrac{3-2}{3}\right)^2+\dfrac{1}{3}\\\\=\dfrac{1}{4}\left(\dfrac{1}{3}\right)^2+\dfrac{1}{3}=\dfrac{1}{4}\cdot\dfrac{1^2}{3^2}+\dfrac{1}{3}=\dfrac{1}{4}\cdot\dfrac{1}{9}+\dfrac{1}{3}=\dfrac{1}{36}+\dfrac{1}{3}\qquad(*)\\\\\text{the common denominator is}\ 36.\\\\36=3\cdot12\to\dfrac{1}{3}=\dfrac{1\cdot12}{3\cdot12}=\dfrac{12}{36}\\\\(*)\qquad=\dfrac{1}{36}+\dfrac{12}{36}=\dfrac{1+12}{36}=\dfrac{13}{36}

4 0
3 years ago
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