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Aleksandr-060686 [28]
3 years ago
13

If x=2 calculate the value of x cubed + x

Mathematics
1 answer:
Montano1993 [528]3 years ago
4 0
X cubed (³) + x

 x³ + x   Plug in 2 for x
2³ + 2   Cube 2 (2 x 2 x 2)
 8 + 2   Add 
   10
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I need help with this plz
emmasim [6.3K]

Answer:

x^{15}

Step-by-step explanation:

Distribute the ^3 on top

(27 x^{6} y^{-9})

distribute the ^ -9 on bottom, only to what is in the parenthesis

(27 x^{-9} y^{-9})

the 27's cross out, the y^{-9} 's cross out

x^{6}/ x^{-9} is left

move the  x^{-9} to the top of fraction to change its sign

x^{6} · x^{9} = x^{15}

3 0
3 years ago
F(x)=8x^2-2x+3<br> g(x)=12x^2+4x-3<br> what is h(x)=f(x)-g(x)?
Trava [24]

Answer: h(x)=-4x^2-6x+6

Step-by-step explanation:

To find the function h(x), you need to subtract the function f(x)=8x^2-2x+3 and the function g(x)=12x^2+4x-3.

h(x)=f(x)-g(x)\\h(x)=8x^2-2x+3-(12x^2+4x-3)

Distribute the negative sign:

h(x)=8x^2-2x+3-12x^2-4x+3

Now you can add the like terms:

h(x)=-4x^2-6x+6

Therefore, you get that the function h(x) is:

 h(x)=-4x^2-6x+6

6 0
3 years ago
Read 2 more answers
Ted says that 7 tenths multiplied by 10 equals 70 hundredths. Is he correct? Use a place value chart to explain your answers
shutvik [7]
No he isn't..
. 7×10=7
for each time it's multiplied by ten, the decimal point goes back one.
3 0
3 years ago
What are the ordered pairs of the
9966 [12]

Start by writing the system down, I will use y to represent f(x)

y=x^2-5x+3\wedge y=-3

Substitute the fact that y=-3 into the first equation to get,

-3=x^2-5x+3

Simplify into a quadratic form (ax^2+bx+c=0),

x^2-5x+6=0

Now you can use Vieta's rule which states that any quadratic equation can be written in the following form,

x^2+x(m+n)+mn=0

which then must factor into

(x+m)(x+n)=0

And the solutions will be m,n.

Clearly for small coefficients like ours 5,6, this is very easy to figure out. To get 5 and 6 we simply say that m=3, n=2.

This fits the definition as 5=3+2 and 6=2\cdot3.

So as mentioned, solutions will equal to m=3, n=2 but these are just x-values in the solution pairs of a form (x,y).

To get y-values we must substitute 3 for x in the original equation and then also 2 for x in the original equation. Luckily we already know that substituting either of the two numbers yields a zero.

So the solution pairs are (2,0) and (3,0).

Hope this helps :)

5 0
2 years ago
Identifying Cross Sections of Solids
NARA [144]
Prisms is the answer for the question
7 0
2 years ago
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