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Tatiana [17]
3 years ago
15

Ab + c = d solve for b.

Mathematics
1 answer:
astraxan [27]3 years ago
6 0

Answer:

b =

Step-by-step explanation:

ab + c = d

-c          -c

ab = d - c

/a        /a

b = (d - c) / a

Hope this helps!

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Corinne has a job selling magazines. She earns $7.50 per hour plus 20% of the total amount of her sales. She also gets an allowa
maw [93]
PART A
Coefficient
Coefficient h is 7.50
Coefficient s is 0.20

Variable
h and s

Constant
40

PART B
7.50h + 0.20s + 40
= 7.50(25) + 0.20(300) + 40
= 187.5 + 60 + 40
= 287.5
She earns $287.5

PART C
Yes, the coefficient of h would change to 9, the rests are still the same. Because she's no longer receive 7.50 per hour, and start earning 9 per hour, so the coefficient should change.
The expression would be
9h + 0.20s + 40
4 0
3 years ago
Pls help^^^^ <br> i dont understand this hw
7nadin3 [17]

Answer:

h=6y/q∧3

Step-by-step explanation:

8 0
3 years ago
Please help and thank you
tatiyna

Answer:

b_{1}=\frac{2A}{h}-b_{2}

Step-by-step explanation:

Given: A=\frac{1}{2}(b_{1} +b_{2})h

We need to completely isolate b_{1} to solve.

A=\frac{1}{2}(b_{1} +b_{2})h

A=(\frac{1}{2}b_{1} +\frac{1}{2} b_{2})h

A=\frac{1}{2}b_{1} h+\frac{1}{2}b_{2}h

-\frac{1}{2}b_{1}h+A=\frac{1}{2}b_{2}h

-\frac{1}{2}b_{1}h=-A+\frac{1}{2}b_{2}h

-\frac{1}{2}b_{1}=\frac{-A}{h}+\frac{1}{2}b_{2}

Finally, multiply both sides by -2 to completely isolate b_{1}.

b_{1}=\frac{2A}{h}-b_{2}

5 0
3 years ago
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i dint understand it is this for school?

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