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3 years ago

A relation is:

Mathematics

2 answers:

krok68 [10]3 years ago

8 0

D. X and y values written in the form of (x,y)

kodGreya [7K]3 years ago

7 0

The answer would be D since x,y is a function

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Factor f(x) = 6x^4 - 9x^3 - 57x^2 - 18x +24

Kryger [21]

3(x+1)(2x-1)(x-4)(x+2)

7 0

3 years ago

In a right triangle ABC, C is the right angle. What does cosB equal?

Montano1993 [528]

Given that,

ABC is a right angle triangle, C is the right angle.

To find,

cosB = ?

Solution,

The sum of angle of a triangle is equal to 180 degrees. So,

∠A + ∠B + ∠C = 180°

Put ∠C = 90°

∠A + ∠B + 90° = 180°

∠A + ∠B = 90°

Taking cos with each term.

cosA+cosB = cos (90)

cosA+cosB = 0

cosB=-sinA

Hence, cosB = sinA.

8 0

3 years ago

Solve for x:a(a²+b²)x²+b²x-a

m_a_m_a [10]

Answer:

x = a/(a² + b²) or x = -1/a

Step-by-step explanation:

a(a²+ b²)x² + b²x - a =0

Use the quadratic equation formula:

$x = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a} =\dfrac{-b\pm\sqrt{D}}{2a}$

1. Evaluate the discriminant D

D = b² - 4ac = b⁴ - 4a(a² + b²)(-a) = b⁴ + 4a⁴ + 4a²b² = (b² + 2a²)²

2. Solve for x

$\begin{array}{rcl}x & = & \dfrac{-b\pm\sqrt{D}}{2a}\\\\ & = & \dfrac{-b^{2}\pm\sqrt{(b^{2}+2a^{2})^{2}}}{2a(a^{2} + b^{2})}\\\\ & = & \dfrac{-b^{2}\pm(b^{2}+ 2a^{2})}{2a(a^{2} + b^{2})}\\\\x = \dfrac{-b^{2}+(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}&\qquad& x =\dfrac{-b^{2}-(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}\\\\x =\dfrac{-b^{2}+(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}&\qquad& x =\dfrac{-b^{2}-(b^{2} +2a^{2})}{2a(a^{2} + b^{2})}\\\\\end{array}$

$\begin{array}{rcl}x = \large \boxed{\mathbf{\dfrac{a}{a^{2} + b^{2}}}}&\qquad& x =\dfrac{-b^{2}-(b^{2} +2a^{2})}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\dfrac{-2b^{2}- 2a^{2}}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\dfrac{-2(a^{2}+ b^{2})}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\large \boxed{\mathbf{-\dfrac{1}{a}}}\\\\\end{array}$

5 0

3 years ago

Find the measure of ∠C if ∠A = 3 2 x + 20 ∠B = 7 2 x + 20 ∠C = 5 2 x + 40 ∠D = 3 2 x + 10 A) 65° B) 76° C) 95° D) 115°

Rudiy27

The sum of the angles of a quadrilateral is 360°.
$\left(\dfrac{3}{2}x+20\right)+\left(\dfrac{7}{2}x+20\right)+\left(\dfrac{5}{2}x+40\right)+\left(\dfrac{3}{2}x+10\right)=360\\\\9x+90=360\\\\x=\dfrac{270}{9}=30$

Given that x=30, the measure of ∠C is
∠C = (5/2)×30 +40 = 115

The appropriate choice is ...
D) 115°

5 0

3 years ago

Read 2 more answers

Write the missing decimal so the each pair adds to 1

oee [108]

Answer:

top one is 0.6 bottom one is 0.1

7 0

3 years ago