Answer:
18 and 21
Step-by-step explanation:
Let the smaller number = 3x
Let the larger number = 3x + 3
The three and the plus 3 insure that the numbers are multiples of 3 and are consecutive.
3* (3x + 3) = 7/10 * 5 (3x) Multiply both sides by 10
30*(3x + 3) = 7 * 5 * 3x Remove the brackets
90x + 90 = 7 * 5 * 3x Combine the right
90x + 90 = 105x Subtract 90x from both sides.
<u>-90x -90x</u>
90 = 15x Divide by 15
x = 90/15
x = 6
Let's see if it works.
3*(3x + 3) = 3*(18 + 3) = 3 * 21 = 63
7/10 * 5 *3x = 7/10 * 5 * 3*6 = 630 / 10 = 63
