Question

2x+3y=3 and -10x+2y=-32

Answer 1

2x + 3y = 3

-10x + 2y = -32

Solve using the substitution method.

Solve for x in the first equation.

2x + 3y = 3

Subtract 3y from both sides.

2x = 3 - 3y

Divide both sides by 2.

x = $\frac{3}{2}$ - $\frac{3}{2}$y

Plug x into the second equation.

-10($\frac{3}{2}$ - $\frac{3}{2}$y) + 2y = -32

Distribute -10 inside the parentheses.

-15 + 15y + 2y = -32

Combine like terms.

-15 + 17y = -32

Add 15 to both sides.

17y = -17

Divide both sides by 17.

y = -1

Plug y into the first equation.

2x + 3(-1) = 3

Multiply 3 by -1.

2x - 3 = 3

Add 3 to both sides.

2x = 6

Divide both sides by 2.

x = 3

x = 3;

y = -1