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mr_godi [17]
3 years ago
5

Find S8 for the arithmetic series 10+ ...-144.

Mathematics
1 answer:
Serhud [2]3 years ago
7 0

Answer:

S_{8} = - 536

Step-by-step explanation:

The n th term of an arithmetic series is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 10 and a_{n} = - 144 , thus

10 + (n - 1)d = - 144 ( subtract 10 from both sides )

(n - 1)d = - 154

The sum to n terms of an arithmetic series is

S_{n} = \frac{n}{2} [ 2a₁ + (n - 1)d ] , thus

S_{8} = \frac{8}{2} [ (2 × 10) + (- 154) ]

    = 4(20 - 154)

    = 4 × - 134

    = - 536

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