Answer:
The graphs of the two function will not intersect.
Step-by-step explanation:
We are given a quadratic function f(x).
Also g(x) is given by a set of values as:
x g(x)
1 -1
2 0
3 1
As g(x) is a linear function hence we find out the equation of g(x) by the slope intercept form of a line: y=mx+c
let g(x)=y
when x=1 , g(x)=-1
-1=m+c----(1)
when x=2 , g(x)=0
0=2m+c------(2)
Hence, on solving (1) and (2) by method of elimination we get:
m=1 and c=-2
Hence, the equation of g(x) is:
g(x)=x-2
So clearly from the graph we could see that the graph of the two functions will never intersect.
You would multiply the power by the powers of both exponents
2 × 3 = 6 so a^6
3 × 4 = 12 so b^12
Answer is
a^6b^12
Answer:
What do you mean by that?
The given equations are
(1)
(2)
When t=0, obtain
Obtain derivatives of (1) and find x'(0).
x' (t+1) + x - 4√x - 4t*[(1/2)*1/√x = 0
x' (t+1) + x - 4√x -27/√x = 0
When t=0, obtain
x'(0) + x(0) - 4√x(0) = 0
x'(0) + 9 - 4*3 = 0
x'(0) = 3
Here, x' means
.
Obtain the derivative of (2) and find y'(0).
2y' + 4*(3/2)*(√y)*(y') = 3t² + 1
When t=0, obtain
2y'(0) +6√y(0) * y'(0) = 1
2y'(0) = 1
y'(0) = 1/2.
Here, y' means
.
Because
, obtain
Answer:
The slope of the curve at t=0 is 1/6.
Answer:
B
Step-by-step explanation:
you need to divide both 15 and 25 by 5
15 divided by 5 = 3
25 divided by 5 = 5
^^
