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kykrilka [37]
2 years ago
14

Name 15 song that you love and tell me who they are by

SAT
2 answers:
Sergio039 [100]2 years ago
6 0

1.Fake love by BTS

2.Let me down slowly by Alec benjamin

3.Outrunning karma by Alec Benjamin

4.Mic drop by BTS

5.Blood sweat and tears By BTS

6.Spring break by BTS

7.Always you by Astro

8.As if it's your last Black-pink

9.Panic room by AU/RA

10. Working by Jungkook from BTS(solo)

11.House of cards By BTS

12.Teddy bear by Melnie Martinez

13.Piggyback By Melanie Martinez

14. When the party's overBy Billie Ellish

15.SewSaw by Suga (BTS)

stealth61 [152]2 years ago
6 0

Love Lies - Khalid feat. Normani

bury a friend - Billie Eilish

lovely - Billie Eilish feat. Khalid

Without Me - Halsey

Walk on Water - Thirty Seconds to Mars

Faded - Alan Walker

Happier - Marshmello feat. Bastille

Sweet but Psycho - Ava Max

Perfect - Ed Sheeran

Guys My Age - Hey Violet

Home with You - Madison Beer

Why - Sabrina Carpenter

Beautiful - Bazzi feat. Camila Cabello

Paris - The Chainsmokers

Pacify Her - Melanie Martinez

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Complete Question:

The mean life of a large shipment of CFLs is equal to 7,500 hours. The population standard deviation is 1,000 hours. A random sample of 64 CFLs indicate a sample life of 7,250  hours.

1. State the Null and Alternative Hypothesis.

2. At the 0.05 level of significance, is there evidence that mean life is different from 7,500 hours.

3. Construct a 95% confidence interval estimate of the population mean life of the CFLs.

4. Compute the p-value and interpret its meaning.

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-2, (7005, 7450), 0.045

Explanation:

1).

H₀: mean of life shipment is 7500 hours

the hypothesis are outlined as follows

H₀: \mu = 7500

H₁: \mu \neq 7500

where, n = 64, x = 7250, \sigma =1000 hours

Test statistics:

Z = \frac{7250-7500}{\frac{1000}{\sqrt{64}} } \\\\Z = -2

Our conclusion from the above result is that there is sufficient evidence to say that the mean life is different from 7500 hours

2). 95% confidence Interval for the population mean \mu is

[7250-1.96\times \frac{1000}{\sqrt{64}},7250+1.96\times \frac{1000}{\sqrt{64}} ]\\\\(7005,7495)

3).

the p-value is given by

p-value =2P(Z\leq -|z|)\\\\p-value =2P(Z\leq -|2|)\\\\p-value = 0.0455

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