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3 years ago

11

It cost $76.86 to redecorate Wiley’s room. Wiley’s mother let Wiley spend some of the money on posters. The bedspread and rugs c

ost $58.29.
How much did Wiley spend on the posters?

A.
$18.57

B.
$22.63

C.
$28.67

D.
$135.15

2 answers:

Fynjy0 [20]3 years ago

6 0

It would be $18.57. If you subtract $58.29 from $76.86, you get the answer

mamaluj [8]3 years ago

5 0

A is the answer bassically

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Write a quadratic function f whose zeros are - 5 and 7.

weeeeeb [17]

Our two binomials are (X-5)(X-7)

If we FOIL those two terms [x*x = x2; x*-7 = -7x; x*-5 = -5x; -5*-7 = 35] and combine the like terms, we're left with one of many quadratic function
Answer
x2-12x+35

3 0

4 years ago

PLEASE HELP ILL MARK BRAINLIEST !!!

Alexus [3.1K]

Answer:

a) the common difference is 20

b) $x_8=115 , x_{12}=195$

c) the common difference is -13

d) $a_{12}=52, a_{15}=13$

Step-by-step explanation:

a) what is the common difference of the sequence xn

Looking at the table, we get x_3=16, x_4=36 and x_5= 56

Deterring the common difference by subtracting x_4 from x_3 we get

36-16 =20

So, the common difference is 20

b) what is x_8? what is x_12

The formula used is: $x_n=x_1+(n-1)d$

We know common difference d= 20, we need to find $x_1$

Using $x_3=16$ we can find $x_1$

$x_n=x_1+(n-1)d\\x_3=x_1+(3-1)d\\15=x_1+2(20)\\15=x_1+40\\x_1=15-40\\x_1=-25$

So, We have $x_1 = -25$

Now finding $x_8$

$x_n=x_1+(n-1)d\\x_8=x_1+(8-1)d\\x_8=-25+7(20)\\x_8=-25+140\\x_8=115$

So, $\mathbf{x_8=115}$

Now finding $x_{12}$

$x_n=x_1+(n-1)d\\x_{12}=x_1+(12-1)d\\x_{12}=-25+11(20)\\x_{12}=-25+220\\x_{12}=195$

So, $\mathbf{x_{12}=195}$

c) what is the common difference of the sequence $a_m$

Looking at the table, we get a_7=104, a_8=91 and a_9= 78

Deterring the common difference by subtracting a_7 from a_8 we get

91-104 =-13

So, the common difference is -13

d) what is a_12? what is a_15?

The formula used is: $a_n=a_1+(n-1)d$

We know common difference d= -13, we need to find $a_1$

Using $a_7=104$ we can find $x_1$

$a_n=a_1+(n-1)d\\a_7=a_1+(7-1)d\\104=a_1+7(-13)\\104=a_1-91\\a_1=104+91\\a_1=195$

So, We have $a_1 = 195$

Now finding $a_{12}$ , put n=12

$a_n=a_1+(n-1)d\\a_{12}=a_1+(12-1)d\\a_{12}=195+11(-13)\\a_{12}=195-143\\a_{12}=52$

So, $\mathbf{a_{12}=52}$

Now finding $a_{15}$ , put n=15

$a_n=a_1+(n-1)d\\a_{15}=a_1+(15-1)d\\a_{15}=195+14(-13)\\a_{15}=195-182\\a_{15}=13$

So, $\mathbf{a_{15}=13}$

5 0

3 years ago

Look at the photo.(15 pts )

horrorfan [7]

I thought i know but i don’t sorry

8 0

3 years ago

Read 2 more answers

Pythagorean Theorema a=24 b=26 c=?

fredd [130]

Answer: 2√313

Step-by-step explanation:

Pythagorean theorem: a²+b²=c²

c²=a²+b²

c²=24²+26²

c²=576+676

c²=1252

c=√1252

c=2√313

Hope this helps!! :)

Please let me know if you have any question or need any further explanation

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3 years ago

What is the square root of 325 rounded to two decimal places?

hammer [34]

The square root of 325 is 18.03

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4 years ago