Answer:
Step-by-step explanation:
We are given that a and b are rational numbers where
and x is irrational number .
We have to prove a+bx is irrational number by contradiction.
Supposition:let a+bx is a rational number then it can be written in
form
where
where p and q are integers.
Proof:
After dividing p and q by common factor except 1 then we get

r and s are coprime therefore, there is no common factor of r and s except 1.
where r and s are integers.


When we subtract one rational from other rational number then we get again a rational number and we divide one rational by other rational number then we get quotient number which is also rational.
Therefore, the number on the right hand of equal to is rational number but x is a irrational number .A rational number is not equal to an irrational number .Therefore, it is contradict by taking a+bx is a rational number .Hence, a+bx is an irrational number.
Conclusion: a+bx is an irrational number.
Answer:
∠ A = 66°
Step-by-step explanation:
Supplementary angles sum to 180° thus
∠ A + ∠ B = 180 , substitute values
2x - 14 + 3x - 6 = 180 , that is
5x - 20 = 180 ( add 20 to both sides )
5x = 200 ( divide both sides by 5 )
x = 40
Thus
∠ A = 2x - 14 = 2(40) - 14 = 80 - 14 = 66°
Answer: 4v^4 u^2
Step-by-step explanation:
Sqrt (53) = 10 * sqrt (0.53)
0.53 = 64/121
sqrt (0.53) = sqrt (64)/ sqrt (121) = 8/11 = 0.7273
Therefore sqrt (53) = 10 * 0.7273 = 7.27
sqrt (108) = 10 * sqrt (1.08)
sqrt (1.08) = sqrt (676/625) = 26/25 = 1.04
Therefore sqrt (108) = 10 * 1.04 = 10.4
sqrt (128) = 10 * sqrt (1.28)
sqrt (1.28) = sqrt (289/225) = 17/15 = 1.133
Therefore sqrt (108) = 10 * 1.133 = 11.33