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musickatia [10]
4 years ago
15

A bag contains 15 marbles. The probability of randomly selecting a green marble is 1/3.The probability of randomly selecting a g

reen marble, replacing it, and then randomly selecting a red marble is 1/15. What is the probability of randomly selecting a red marble?
Mathematics
2 answers:
devlian [24]4 years ago
8 0

the answer is 1/5. I got the answer from Quizlet and it was correct

WARRIOR [948]4 years ago
5 0
The probability of randomly selecting a red marble is 1/5. You get that by dividing 1/15 by 1/3
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Jim spent $46.16 on some mulch and one shovel. Each bag of mulch costs $3.49 and the shovel cost $14.75. How many bags of mulch
mezya [45]
To find the amount he spent on bags of mulch you must take the cost of the shovel away from the total, giving the equation:
46.16-14.75=3.49x
To covert this to whole numbers, multiply by 100
4616-1475=349x
3141=349x
x=9
4 0
4 years ago
You are conducting a study to see if the proportion of voters who prefer Candidate A is significantly more than 47%. With Ha : p
rodikova [14]

Answer:

The p-value is 0.0229

Step-by-step explanation:

With H_{a}: p > 0.47 we have an upper-tail alternative. Because the p-value is defined as the probability of getting a value at least as extreme as the value observed. The observed value is given by the test statistic z = 1.997 which comes from a standard normal distribution. Therefore, we compute the p-value in the following way P(Z > 1.997) = 0.0229, i.e., the p-value is 0.0229

3 0
3 years ago
What is the lateral area of the prism?<br><br> cm2
laiz [17]
LA = (2l + 2w)h

Plug in what we know:

LA = (2(11) + 2(7))(4)

Multiply:

LA = (22 + 14)(4)

Add:

LA = 36(4)

Multiply:

LA = 144
3 0
3 years ago
In a survey in 2010, the population of two plant species were found to be growing exponentially. Their growth is given by these
Lunna [17]

If we want to find when the population of species A will be equal to the population of species B, we need to see when the two equations for the population of each species are equal, ie. equate them and solve for t. Thus:

2000e^(0.05t) = 5000e^(0.02t)

(2/5)e^(0.05t) = e^(0.02t) (Divide each side by 5000)

2/5 = e^(0.02t) / e^(0.05t) (Divide each side by e^(0.05t))

2/5 = e^(-0.03t) (use: e^a / e^b = e^(a - b))

ln(2/5) = -0.03t (use: if b = a^c, then loga(b) = c )

t = ln(2/5) / -0.03 (Divide each side by -0.03)

= 30.54 (to two decimal places)

Therefor, the population of species A will be equal to the population of species B after 30.54 years.

I wasn't entirely sure about the rounding requirements so I've left it rounded to two decimal places.

6 0
3 years ago
A pile of 37 coins consists of nickels and dimes. The total value
tensa zangetsu [6.8K]

Answer:

25 dimes & 12 nickels

Step-by-step explanation:

Let there be "n" nickels and "d" dimes

Total, there are 37 of them, so we can write:

n + d = 37

Also, valueof nickel is 0.05 and value of dime is 0.10 (in dollars) and total value of these 37 coins is 3.10, so we can write:

0.05n + 0.10d = 3.10

Now we can write first equation as:

n + d = 37

n = 37 - d

Replace this into equation 2 and solve for d:

0.05n + 0.10d = 3.10

0.05(37 - d) + 0.10d = 3.10

1.85 - 0.05d + 0.10d = 3.10

0.05d = 3.10 - 1.85

0.05d = 1.25

d = 1.25/0.05

d = 25

Now, n = 37 - d, n = 37 - 25 = 12

So,

There are 25 dimes & 12 nickels

7 0
3 years ago
Read 2 more answers
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