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3 years ago

The value of a car declined 20% per year. what percent of the original value remains after 2 years

Mathematics

1 answer:

GalinKa [24]3 years ago

5 0

60% is answer...20% is taken each year so After 2 yrs it's 40% less 100-40 is 60

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Nancy's garden has the dimensions shown 4 1/2 yard<br><br> 3 3/4 yd . She need find the area

Marina86 [1]

Answer:

The area of Nancy's garden is $16\frac{7}{8}\ yd^{2}$

Step-by-step explanation:

I assume that the Nancy's garden is a rectangle shape

To find the area first convert mixed number to an improper fraction

$4\frac{1}{2}\ yd=\frac{4*2+1}{2}=\frac{9}{2}\ yd$

$3\frac{3}{4}\ yd=\frac{3*4+3}{4}=\frac{15}{4}\ yd$

Therefore

The area is equal to

$A=\frac{9}{2}*\frac{15}{4}=\frac{135}{8}\ yd^{2}$

convert to mixed number

$\frac{135}{8}\ yd^{2=\frac{128}{8}+\frac{7}{8}=16\frac{7}{8}\ yd^{2}$

4 0

3 years ago

A 12 ounce bottle of cleaner cost $3.74 a 16 ounce bottle of cleaner cost $5.34 which bottle would be the best spot which cost l

Valentin [98]

Answer:

12 ounce bottle

Step-by-step explanation:

12 x 3 = 36

16 x 5 = 80

So, that means the 12 ounce bottle is cheaper. :)

5 0

3 years ago

What's 3z - 4 and 2z + 5

Pavlova-9 [17]

The answer to this question would b:
=5x−9

8 0

3 years ago

Assume that the terminal side of thetaθ passes through the point (negative 12 comma 5 )(−12,5) and find the values of trigonomet

zmey [24]

Answer:

$\sin \theta = \dfrac{5}{13}$ and $\sec \theta = -\dfrac{13}{12}$

Step-by-step explanation:

Assume that the terminal side of thetaθ passes through the point (−12,5).

In ordered pair (-12,5), x-intercept is negative and y-intercept is positive. It means the point lies in 2nd quadrant.

Using Pythagoras theorem:

$hypotenuse^2=perpendicular^2+base^2$

$hypotenuse^2=(5)^2+(12)^2$

$hypotenuse^2=25+144$

$hypotenuse^2=169$

Taking square root on both sides.

$hypotenuse=13$

In a right angled triangle

$\sin \theta = \dfrac{opposite}{hypotenuse}$

$\sin \theta = \dfrac{5}{13}$

$\sec \theta = \dfrac{hypotenuse}{adjacent}$

$\sec \theta = \dfrac{13}{12}$

In second quadrant only sine and cosecant are positive.

$\sin \theta = \dfrac{5}{13}$ and $\sec \theta = -\dfrac{13}{12}$

6 0

3 years ago

GiReady

vladimir2022 [97]

Answer: Decreased by 12 students

Step-by-step explanation:

40-28=12

7 0

3 years ago

Read 2 more answers