Answer:

Therefore the probability that a randomly selected student has time for mile run is less than 6 minute is 0.0618
Step-by-step explanation:
Normal with mean 6.88 minutes and
a standard deviation of 0.57 minutes.
Choose a student at random from this group and call his time for the mile Y. Find P(Y<6)


y ≈ normal (μ, σ)
The z score is the value decreased by the mean divided by the standard deviation

Therefore the probability that a randomly selected student has time for mile run is less than 6 minute is 0.0618
Answer: C
Step-by-step explanation: Divide the mass value by 35.274
8.40/3 = £2.80 each
...............
Answer:
2x2-3x-5=0
Step-by-step explanation:
(2x2 - 3x) - 5 = 0
Answer:
2over1 multiply by 6over 3then you devide both sides by the given numbers then answer is 6woal number 1out of 6