Answer:

Therefore the probability that a randomly selected student has time for mile run is less than 6 minute is 0.0618
Step-by-step explanation:
 Normal with mean 6.88 minutes and 
a standard deviation of 0.57 minutes.
Choose a student at random from this group and call his time for the mile Y. Find P(Y<6) 


y ≈ normal (μ, σ)
The z score is the value decreased by the mean divided by the standard deviation
 
Therefore the probability that a randomly selected student has time for mile run is less than 6 minute is 0.0618
 
        
             
        
        
        
Answer: C
Step-by-step explanation: Divide the mass value by 35.274
 
        
             
        
        
        
8.40/3 = £2.80 each
...............
        
             
        
        
        
Answer:
2x2-3x-5=0 
Step-by-step explanation:
(2x2 -  3x) -  5  = 0 
 
        
                    
             
        
        
        
Answer:
2over1 multiply by 6over 3then you devide both sides by the given numbers then answer is 6woal number 1out of 6