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sergiy2304 [10]
3 years ago
15

Mrs. Nelson has a rectangular flower box that is 5 feet long and 2 feet tall. She wants the width of the box to be no more than

5 feet. If the widthis a whole number, what are the possible volumes for the flower box
Mathematics
1 answer:
Reika [66]3 years ago
7 0
The possible volumes are 5 ft long, 4 ft wide and 2 ft deep or 5 ft long, 3 ft wide and 2 ft deep or 5 ft long, 2 ft wide and 2 ft deep or 5 ft long, 1 ft wide and 2 ft deep
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HELP <br><br>MMEEE!! i will give brainly
LUCKY_DIMON [66]

Answer:

the answer is 28 in

hope this helps

8 0
2 years ago
Read 2 more answers
The graph shows the distance y, in feet, a pendulum moves to the right (positive displacement) and to the left (negative displac
Dmitriy789 [7]

Answer:

<u>2.5 seconds</u>

Step-by-step explanation:

Resting position is at y = zero which mean x intercept

So, we need to find the time between two consecutive points of intersection with the x-axis.

Which mean it is the half period of the given function as it is a sine wave

From the graph we can deduce that

<u>2.5 seconds</u> are required for the pendulum to move from its resting position, swing in one direction and return to its resting position.

6 0
3 years ago
Please help and explain!!!!!
FinnZ [79.3K]

Let x be the amount of the 30% alloy and y the amount of the 60% alloy the metalworker will use. However much is used, the final alloy will have a mass of

x+y=100

kilograms. For each kg of the 30% alloy used, 0.3 kg is copper; similary, each kg of the 60% alloy contributes 0.6 kg, so that

0.3x+0.6y=0.54(x+y)=54

Now,

x+y=100\implies y=100-x

\implies0.3x+0.6(100-x)=54

\implies60-0.3x=54

\implies0.3x=6

\implies x=20

\implies y=100-20=80

6 0
4 years ago
-3(1 + 6x) = 14 - x<br> How do you solve this?
mezya [45]
-3(1+6x) = 14 - x
-3 -18x = 14 -x
-18x +x = 14 + 3
-17x = 17
x = -17/17
x = -1
Therefore x is equal to -1.
4 0
4 years ago
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5/4 to 3/8 as a percent change
Digiron [165]
Well, what's the diffrence from 5/4 to 3/8?

\bf \cfrac{5}{4}-\cfrac{3}{8}\qquad \stackrel{\textit{LCD is 8 clearly}}{\implies }\qquad \cfrac{10-3}{8}\implies \cfrac{7}{8}

so, if we take 5/4 to be the 100%, what is 7/8 off of it in percentage anyway?

\bf \begin{array}{ccll}&#10;amount&\%\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;\frac{5}{4}&100\\\\&#10;\frac{7}{8}&x&#10;\end{array}\implies \cfrac{\quad \frac{5}{4}\quad }{\frac{7}{8}}=\cfrac{100}{x}\implies \cfrac{5}{4}\cdot \cfrac{8}{7}=\cfrac{100}{x}&#10;\\\\\\&#10;\cfrac{40}{28}=\cfrac{100}{x}\implies x=\cfrac{28\cdot 100}{40}
5 0
3 years ago
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