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3 years ago

14

Determine the standard form of an equation that passes through (2,2) and (-6,4).

1 answer:

Mumz [18]3 years ago

7 0

Slope = (4 - 2)/(-6 - 2)= 2/-8 = -1/4

y = mx + b
2 = -1/4(2) + b
2 = -1/2 + b
b = 5/2

equation
y = -1/4x + 5/2
4y = -x + 10
x + 4y = 10

answer
<span>A) x+4y=10</span>

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Using long division to find the quotient, what changes do you first

lora16 [44]

Answer:

$\frac{125x^3 - 8}{5x - 2} = 25x^2 + 10x +4$

Step-by-step explanation:

Given

$Dividend = 125x^3 - 8$

$Divisor = 5x - 2$

Required

Determine the quotient

See attachment for complete process.

First, divide 125x^3 by 5x

$\frac{125x^3}{5x} =25x^2$

Write $25x^2$ at the top

Multiply $5x - 2$ by $25x^2$

$= 125x^3 - 50x^2$

Subtract from 125x^3 - 8

i.e.

$125x^3 - 8 - (125x^3 - 50x^2) = 50x^2 - 8$

Step 2:

Divide 50x^2 by 5x

$\frac{50x^2}{5x} = 10x$

Write $10x$ at the top

Multiply $5x - 2$ by $10x$

$= 50x^2 - 20x$

Subtract from 50x^2 - 8

i.e.

$50x^2 - 8 - (50x^2 - 20x) = 20x - 8$

Step 3:

Divide 20x by 5x

$\frac{20x}{5x} = 4$

Write $4$ at the top

Multiply $5x - 2$ by $4$

$= 20x - 8$

Subtract from 20x - 8

i.e.

$20x - 8 - (20x - 8) = 0$

Hence:

$\frac{125x^3 - 8}{5x - 2} = 25x^2 + 10x +4$

8 0

3 years ago

The lengths (in miles) of two highways after t years of construction can be modeled by 20t + 150 and 15t+ 200. What is the diffe

Mashutka [201]

Step-by-step explanation:

13.5 is the difference of the length of the roads

3 0

2 years ago

At 3pm, the length of the shadow of a thin vertical pole standing on level ground is the same as the height of the pole. A while

aliya0001 [1]

Answer: The height of the pole is 175.97 ( approx )

Step-by-step explanation:

Let the height of the pole is x cm,

Also, let the angle of elevation of the sun to the pole at 3 pm is $\theta$

Thus, by the question,

$tan\theta = \frac{\text{ The height of the pole}}{\text{ The height of the shadow}}$

$\implies tan\theta = \frac{x}{x}$ ( at 3pm the height of shadow = height of the pole)

$\implies tan\theta = 1$

$\implies \theta = 45^{\circ}$

Again, according to the question,

When the angle of elevation is $(\theta - 12^{\circ})$ ,

The height of shadow = x + 95,

$\implies tan(45-12)^{\circ}=\frac{x}{x+95}$

$\implies tan 33^{\circ}=\frac{x}{x+95}$

$\implies tan 33^{\circ}x + 95\times tan33^{\circ}=x$

$\implies tan 33^{\circ}x - x = - 95\times tan33^{\circ}$

$\implies -0.3505924068 x = - 61.6937213538$

$x=175.969930202\approx 175.97\text{ cm}$

4 0

3 years ago

Someone please help me with #2

mario62 [17]

<em>Good luck, you'll need it :)</em>

6 0

3 years ago

A flower has ten pedals.During a storm,five of the pedals fall off.Write a decimal to show what part of the pedals is left

olga nikolaevna [1]

The answer is .5 meaning half (1/2) of the petals fell off.

7 0

3 years ago