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2 years ago

Solve cot x + 2cot x * sin x = 0 for U^ <= x<=180

Mathematics

1 answer:

nekit [7.7K]2 years ago

3 0

Answer:

Step-by-step explanation:

hello :

cot x + 2cot x sin x = 0 0≤ x≤ 180

cotx(1+2sinx) =0 means : cotx=0 or 1+2sinx=0

1) cotx=0 so : cosx=0 and sinx ≠ 0 because cotx = cosx/sinx

when : 0≤ x≤ 180 : x=90°

2) 1+2sinx=0 means : sinx = -1/2

when : 0≤ x≤ 180 : no solutions because : sinx ≥ 0

conclusion : one solution : x=90°

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Given: ABCD is a ∥-gram, BF ⊥ CD , BE ⊥ AD, Prove: △ABE∼△CBF

drek231 [11]

Answer:

Hence proved △ABE∼△CBF.

Step-by-step explanation:

Given,

ABCD is a parallelogram.

BF ⊥ CD and

BE ⊥ AD

To Prove : △ABE∼△CBF

We have drawn the diagram for your reference.

Proof:

Since ABCD is a parallelogram,

So according to the property of parallelogram opposite angles are equal in measure.

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And given that BF ⊥ CD and BE ⊥ AD.

So we can say that;

$m\angle F=m\angle E=90\°$ ⇒2

Now In △ABE and △CBF

∠A = ∠C (from 1)

∠E = ∠F (from 2)

So by A.A. similarity postulate;

△ABE∼△CBF

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2 years ago

5(y+2/5)=-13<br> what is y

jolli1 [7]

Answer:

y=11/5

Step-by-step explanation:

first divide by 5 on both sides

y+2/5=-13/5

subtract 2/5 on both sides to isolate the y

y=11/5

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2 years ago

A triangle is graphed in the coordinate plane. The vertices of the triangle have coordinates (–3, 1), (1, 1), and (1, –2). What

vladimir2022 [97]

Answer:

The perimeter of the triangle is $12\ units$

Step-by-step explanation:

Let

$A(-3,1),B(1,1),C(1,-2)$

we know that

The perimeter of triangle is equal to

$P=AB+BC+AC$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

$A(-3,1),B(1,1)$

substitute in the formula

$AB=\sqrt{(1-1)^{2}+(1+3)^{2}}$

$AB=\sqrt{(0)^{2}+(4)^{2}}$

$AB=4\ units$

step 2

Find the distance BC

$B(1,1),C(1,-2)$

substitute in the formula

$BC=\sqrt{(-2-1)^{2}+(1-1)^{2}}$

$BC=\sqrt{(-3)^{2}+(0)^{2}}$

$BC=3\ units$

step 3

Find the distance AC

$A(-3,1),C(1,-2)$

substitute in the formula

$AC=\sqrt{(-2-1)^{2}+(1+3)^{2}}$

$AC=\sqrt{(-3)^{2}+(4)^{2}}$

$AC=5\ units$

step 4

Find the perimeter

$P=AB+BC+AC$

substitute the values

$P=4+3+5=12\ units$

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2 years ago