The location of the y value of R' after using the translation rule is -10
<h3>What will be the location of the y value of R' after using the translation rule? </h3>
The translation rule is given as:
(x + 4, y - 7)
The pre-image of R is located at (-17, -3)
Rewrite as
R = (-17, -3)
When the translation rule is applied, we have:
R' = (-17 + 4, -3 - 7)
Evaluate
R' = (-13, -10)
Remove the x coordinate
R'y = -10
Hence, the location of the y value of R' after using the translation rule is -10
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Answer:c
Step-by-step explanation:
when you set (x-6) and (x-1) to zero you get 6 and 1
Step-by-step explanation:
Answer:
The answer is 9x² - 6x - 1
Step-by-step explanation:
∵ (6x³ + x² - 10x - 1) - (6x³ - 8x² - 4x) =
0 + 9x² - 6x - 1 = 9x² - 6x - 1
Answer:
Range=65
Step-by-step explanation:
The highest is 66 the lowest is 1 so 66-1=65
