The factoring method which can be considered for such a cubic tetranomial expression is; factor by grouping sum of cubes.
<h3>What factoring method can be considered for the polynomial?</h3>
It follows from the task content that the order of the Polynomial is 3 and the polynomial is a tetranomial as it contains 4 terms.
On this note, since 3x³ is not a perfect cube, it follows that the best factorisation method for such a polynomial is; factor by grouping sum of cubes.
Read more on factorisation;
brainly.com/question/25829061
#SPJ4
For the given situation we have a total of 259,459,200 permutations.
<h3>
How many permutations are?</h3>
First, how we know that it is a permutation?
Because the order matters, we aren't only selecting 8 out of the 15 people, but these 8 selected also have an order (is not the same thing to finish the race first than fourth, for example).
Then we need to find the number of permutations, to do it, we need to find the numbers of options for each of the 8 positions.
- For the first position there are 15 options.
- For the second position ther are 14 options (one runner already finished).
- For the third position there are 13 options.
- And so on.
Then the total number of permutations (product between the numbers of options) is:
P = 15*14*13*12*11*10*9*8 = 259,459,200
If you want to learn more about permutations:
brainly.com/question/11732255
#SPJ1
Answer:
D.24
Pythagorean states:
hypotenuse^2 = side1^2 + side2^2
30^2 = 18^2 + side2^2
side2^2 = 30^2 - 18^2
side2^2 = 900 - 324
side2^2 = 576
side2 = sqr root 576
side2 = 24
Source: http://www.1728.org/pythgorn.htm
Step-by-step explanation:
Answer:
2x-6
I don't know what you mean by correction, but that's in expression form.
Answer: ur answer would be 27283
Step-by-step explanation:
