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timofeeve [1]
2 years ago
11

What are the variables?

Mathematics
1 answer:
tresset_1 [31]2 years ago
5 0

Answer:

T and R

Step-by-step explanation:

Variables are letters that are a quantity not known yet

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The walls of the kitchen are 8 feet tall. You will only paint three wLLA OF THE KIRCHEN. WHAT IS THE TOTAL WALL AREA OF THE THRE
Anika [276]
You need to include how wide the walls are. but once you find how wide the walls are (X) then multiply it by how tall a the walls are (8 feet) and you will get the area of one wall. Take that answer and multiply it by 3 then multiply that by how much the paint costs
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3 years ago
PLS HELP
sertanlavr [38]

Answer:

C. 76 + 7i

Step-by-step explanation:

49 squared is 7 and since it's negative, it is an imaginary number. Therefore, it is 7i. Which leaves C to be the correct option.

8 0
2 years ago
Pls help thirty points and will do branliest
Luba_88 [7]

The dashed-line triangle is a dilation-reduction, and the scale factor is (1/3).  Note how the former triangle is 1/3 the size of the larger one.

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3 years ago
PLEASE HELP GIVING BRAINEST AWNSER AND ITS WORTH 85 points
Dennis_Churaev [7]

Answer:

H. 10

Step-by-step explanation:

We can write down all the games that can be played (I'm going to use a, b, c, d, and e to symbolize the players)

ab, ac, ad, ae, bc, bd, be, cd, ce, de

As you can see, there are 10 games that are going to be played.

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5 0
2 years ago
Read 2 more answers
Matlab the equation of a circle with its center at x=3 and y=2 is given by , where r is the radius of the circle. first derive t
Blizzard [7]
The equation of a circle with center at (h,k) and radius r is
(x-h)^2+(y-k)^2=r^2
we are given
center is at (3,2)
(x-3)^2+(y-2)^2=r^2
solving for y
(y-2)^2=-1(x-3)^2+r^2
y-2=\sqrt{-1(x-3)^2+r^2}
y=2+\sqrt{-1(x-3)^2+r^2}
take the derivitive to find the slope at any point
\frac{dy}{dx}=((-1)(x-3)^2+r^2))(-x+3)


we can use point slope form
for apoint (h,k) and slope m, the equation is
y-k=m(x-h)
not sure if you want in terms of what
I'll just say for a point (h,k)
so we get
y-k=((-1)(x-3)^2+r^2))(-x+3)(x-h)
where k=2+\sqrt{-1(h-3)^2+r^2}
that's the equation of the tangent line at (h,k) for arbitrary values of r

do the plots and other stuff yourself
7 0
3 years ago
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