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2 years ago

What are the variables?

Mathematics

1 answer:

tresset_1 [31]2 years ago

5 0

Answer:

T and R

Step-by-step explanation:

Variables are letters that are a quantity not known yet

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Help plz dis is a lil importatnete

Goryan [66]

Following order of operations:

3^2 = 9

(10-2) = 8

Now you have :

9 + 8 x 5 -4

Multiplication is next:

9 + 40 -4

Now just add and subtract from left to right:

9 + 40 = 49

49-4 = 45

The answer is 45

8 0

2 years ago

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A car moves at a speed that allows it to move 45 yards in 5⁄4 of a second. How long will it take a car at the same speed to move

Dimas [21]

First, to make things easier, let's turn 5/4 into a decimal given a second is equal to 1000 milliseconds.

5/4 = 1,25

1,25 * 1000 = 1250 milliseconds = 1.25 seconds

So, we've found that 45 yards can be covered in 1.25 seconds. Now we'll use the rule of 3:

45 - 1.25

80 - x

Now we solve:

(80 * 1.25) / 45 = x

100 / 45 = x

2,22... = x

So, according to our answer, 80 yards can be covered in 2,22 seconds, which in fractions would be:

$2,22 =\frac{222}{100} = \frac{111}{50}$

Hope it helped,

BioTeacher101

7 0

2 years ago

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If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar

erma4kov [3.2K]

Answer:

$\frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}$

Step-by-step explanation:

Given

5 tuples implies that:

$n = 5$

$(h,i,j,k,m)$ implies that:

$r = 5$

Required

How many 5-tuples of integers $(h, i, j, k,m)$ are there such that $n\ge h\ge i\ge j\ge k\ge m\ge 1$

From the question, the order of the integers h, i, j, k and m does not matter. This implies that, we make use of combination to solve this problem.

Also considering that repetition is allowed: This implies that, a number can be repeated in more than 1 location

So, there are n + 4 items to make selection from

The selection becomes:

$^{n}C_r => ^{n + 4}C_5$

$^{n + 4}C_5 = \frac{(n+4)!}{(n+4-5)!5!}$

$^{n + 4}C_5 = \frac{(n+4)!}{(n-1)!5!}$

Expand the numerator

$^{n + 4}C_5 = \frac{(n+4)!(n+3)*(n+2)*(n+1)*n*(n-1)!}{(n-1)!5!}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5!}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5*4*3*2*1}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}$

<u><em>Solved</em></u>

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2 years ago

tom is making a rectangular garden. he decides to make the garden 30 ft long by 15 ft wide. Later, tom decides to keep the lengt

UkoKoshka [18]

Width=25 got me m; iyyyyg

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3 years ago

Please answer the picture i put! Thanks Sooo much.

kow [346]

The answer is A and B

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2 years ago

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