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andrew-mc [135]
4 years ago
14

If x varies inversely as y, and x = 3 when y= 8, find y when x=4

Mathematics
1 answer:
gladu [14]4 years ago
6 0

The value of y is 6 when x is 4

Step-by-step explanation:

If x varies inversely as y, then

  • x = \frac{k}{y} , where k is the constant of variation
  • xy = k, you can find k by using the initial values of x and y
  • \frac{x_{1}}{x_{2}}=\frac{y_{2}}{y_{1}}

∵ x varies inversely as y

∴ x = \frac{k}{y}

∵ When x = 3, y = 8

- Substitute these values in the equation to find k

∴ 3 = \frac{k}{8}

- Multiply both sides by 8

∴ 24 = k

∴ The equation of variation is x = \frac{24}{y}

∵ x = 4

- Substitute the value of x in the equation to find y

∴ 4 = \frac{24}{y}

- Multiply both sides by y

∴ 4y = 24

- Divide both sides by 4

∴ y = 6

The value of y is 6 when x is 4

Learn more:

You can learn more about the direct and inverse variation in brainly.com/question/10708697

#LearnwithBrainy

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You need to know the distribution's mean and standard deviation.

\mathbb P(X>100)=0.20\implies\mathbb P(X\le100)=0.80

Transforming to the standard normal distribution, and letting \sigma denote the standard deviation,

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3 years ago
A jet travels 2301 miles against the wind in 3 hours and 2811 miles with the wind in the same amount of time. What is the rate o
astraxan [27]

Answer:

The rate of the jet in still air is 852 miles per hour. The rate of the wind is 85 miles per hour.

Step-by-step explanation:

Let suppose that jet travels uniformly, that is, at constant speed, the expressions for its travels against the wind and with the wind are, respectively:

Against the wind

v -u = \frac{\Delta x_{1}}{\Delta t_{1}}

With the wind

v +u = \frac{\Delta x_{2}}{\Delta t_{2}}

Where:

v - Speed of the jet in still air, measured in miles per hour.

u - Speed of wind, measured in miles per hour.

\Delta x_{1}, \Delta x_{2} - Distances travelled by jet against the wind and with the wind, measured in miles.

\Delta t_{1}, \Delta t_{2} - Times against the wind and with the wind, measured in hours.

By adding both expressions:

2\cdot v = \frac{\Delta x_{1}}{\Delta t_{1}}+\frac{\Delta x_{2}}{\Delta t_{2}}

v = \frac{1}{2}\cdot \left(\frac{\Delta x_{1}}{\Delta t_{1}} + \frac{\Delta x_{2}}{\Delta t_{2}} \right)

Given that \Delta x_{1} = 2301\,mi, \Delta t_{1} = 3\,h, \Delta x_{2} = 2811\,mi and \Delta t_{2} = 3\,h, the speed of the jet is:

v = \frac{1}{2}\cdot \left(\frac{2301\,mi}{3\,h}+\frac{2811\,mi}{3\,h}  \right)

v = 852\,\frac{mi}{h}

The rate of the jet in still air is 852 miles per hour.

Lastly, the rate of the wind is:

u = \frac{\Delta x_{2}}{\Delta t_{2}}-v

u = \frac{2811\,mi}{3\,h}-852\,\frac{mi}{h}

u = 85\,\frac{mi}{h}

The rate of the wind is 85 miles per hour.

 

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