The 12th decades every other day every three days and four days all have 12 in common I think
Since PQ bisects CX at point J, JX=CJ
4y=y+9
-y -y
3y=9
divide by 3
y=3
Answer:
No solution
Step-by-step explanation:
3x + 6y =36
-3x - 6y =0
------------------add
0 ≠ 36
No solution
Step-by-step explanation:
Just sum the number of cows and buffaloes:
2p^2 - p + 4 + p^2 + p + 1 = 3p^2 +5 animals.
