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egoroff_w [7]
3 years ago
7

A student wants to report on the number of meals his friends buy each week. The collected data are below: 4 19 3 3 2 3 2 4 Which

measure of center is most appropriate for this situation and what is its value?
Mathematics
2 answers:
lord [1]3 years ago
7 0

Answer:

Median and Mode.

Step-by-step explanation:

The data could be represented in table form in ascending order as:

 <u>Number of meals </u>                       <u> Frequency</u>

       2                                                     2

        3                                                     3

        4                                                     2

        19                                                    1`

On the basis of the data now we find the mean, median and mode:

Mean= average of the data

Mean=\dfrac{2\times 2+3\times 3+4\times 2+19\times 1}{2+3+2+1}=\dfrac{40}{8}=5

Hence mean is 5.

Median is the central tendency of the data

on looking at our data we see that the Median=3.

also the mode of the data is the entry corresponding to the highest entry.

Hence the highest frequency is 3 and the corresponding value is 3.

Hence, Mode=3

Hence, the most appropriate measure of center for this situation is :

Median and Mode.






Strike441 [17]3 years ago
3 0
The median or the mode which is three, but not the average because there is an outlier in the set, which is 19 and would skew the data higher than it should be.
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4 years ago
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Mr. Green teaches mathematics and his class recently finished a unit on statistics. The student scores on this unit are: 40 47 5
Harrizon [31]

Answer:

Mean = 64.46, Median = 62 and Mode = Bi-modal (50 and 62)

Range of the data is 55.

Step-by-step explanation:

We are given that Mr. Green teaches mathematics and his class recently finished a unit on statistics.

<u>The student scores on this unit are:</u>  40, 47, 50, 50, 50, 54, 56, 56, 60, 60, 62, 62, 62, 63, 65, 70, 70, 72, 76, 77, 80, 85, 85, 95.

We know that Measures of Central Tendency are: Mean, Median and Mode.

  • Mean is calculated as;

                   Mean  =  \frac{\sum X}{n}

where  \sum X = Sum of all values in the data

               n = Number of observations = 24

So, Mean  =  \frac{40+ 47+ 50+ 50+ 50+ 54+ 56+ 56+ 60 +60+ 62+ 62+ 62+ 63+ 65+ 70+ 70+ 72+ 76+ 77+ 80+ 85+ 85+ 95}{24}

=  \frac{1547}{24}  =  64.46

So, mean of data si 64.46.

For calculating Median, we have to observe that the number of observations (n) is even or odd, i.e.;

  • If n is odd, then the formula for calculating median is given by;

                     Median  =  (\frac{n+1}{2})^{th} \text{ obs.}

  • If n is even, then the formula for calculating median is given by;

                     Median  =  \frac{(\frac{n}{2})^{th}\text{ obs.} +(\frac{n}{2}+1)^{th}\text{ obs.}   }{2}

Now here in our data, the number of observations is even, i.e. n = 24.

So, Median  =  \frac{(\frac{n}{2})^{th}\text{ obs.} +(\frac{n}{2}+1)^{th}\text{ obs.}   }{2}

                    =  \frac{(\frac{24}{2})^{th}\text{ obs.} +(\frac{24}{2}+1)^{th}\text{ obs.}   }{2}

                    =  \frac{(12)^{th}\text{ obs.} +(13)^{th}\text{ obs.}   }{2}

                    =  \frac{62 + 62  }{2}  =  \frac{124}{2}  =  62

Hence, the median of the data is 62.

  • A Mode is a value that appears maximum number of times in our data.

In our data, there are two values which appear maximum number of times, i.e. 50 and 62 as these both appear maximum 3 times in the data.

This means our data is Bi-modal with 50 and 62.

  • The Range is calculated as the difference between the highest and lowest value in the data.

                      Range  =  Highest value - Lowest value

                                   =  95 - 40 = 55

Hence, range of the data is 55.

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