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2 years ago

Answer this quick I have 20 minutes 25 points

Mathematics

1 answer:

e-lub [12.9K]2 years ago

6 0

The answer is A. You can comment if u want an explanation :)

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Simplify the following ratios:

jenyasd209 [6]

A) 3:4
b) 2:7
c) 3.5
d) 2:3

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2 years ago

Erica runs 5.3 kilometers every morning. One day, she runs 0.95 kilometers and then stops to take a break. How much further does

Leviafan [203]

Answer:

1foot(ft.)1yard(yd.)1mile(mi.)===12inches(in.)3feet(ft.)5,280feet(ft.)

Step-by-step explanation:

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3 years ago

For a function p(x)= x^2-9, what is the inverse function for the domain [0, infinity\

kkurt [141]

An inverse function is a function that reverses another function, so we have a function called:

$p(x)$

Then, the inverse function will be as follows:

$p^{-1}(x)$

Given that $y = p(x)$ , we need to isolate x in terms of y:

$y = x^{2} -9$
∴ $y+9 = x^{2}$

So:

$x=+\sqrt{y+9}$ and $x=-\sqrt{y+9}$

therefore, exchanging variables x and y:

$y=+\sqrt{x+9}$ and $y=-\sqrt{x+9}$
$p^{-1}(x)=+\sqrt{x+9}$ and $p^{-1}(x)=-\sqrt{x+9}$

Which are the figures shown below.

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3 years ago

Can someone tell me which one it is

IrinaK [193]

Answer:

Step-by-step explanation:

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2 years ago

Liquid A has a density of 0.7g/cm^3

TiliK225 [7]

$\rho = \frac{m}{V} \Rightarrow V=\frac{m}{\rho}$
ρ - density, m - mass, V - volume

Liquid A:
$\rho=0.7 \ \frac{g}{cm^3} \\
m=140 \ g \\
\\ V=\frac{140 \ g}{0.7 \ \frac{g}{cm^3}}=200 \ cm^3$

Liquid B:
$\rho=1.6 \ \frac{g}{cm^3} \\
m=128 \ g \\
\\ V=\frac{128 \ g}{1.6 \ \frac{g}{cm^3}}=80 \ cm^3$

Liquid C:
$m=140 \ g + 128 \ g=268 \ g \\
V=200 \ cm^3 + 80 \ cm^3=280 \ cm^3 \\ \\
\rho=\frac{268 \ g}{280 \ cm^3} \approx 0.96 \ \frac{g}{cm^3}$

The density of liquid C is approximately 0.96 g/cm³.

5 0

3 years ago

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