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matrenka [14]
3 years ago
8

???? I don’t understand how to do this problem

Mathematics
1 answer:
Firdavs [7]3 years ago
6 0

I think you are correct actually.

You might be interested in
Solve 0= 2t^3-21t^2+ 40t
sukhopar [10]
0=2t^3-21^2+40t
switch sides
2t^3-21t^2+40t=0
solve factoring 
t(t-8)(2t-5)=0
using the zero factor principle
t=0

solve
t-8=0:t=8
solve
2t-5=0:t= \frac{5}{2}
t=0,t=8,t= \frac{5}{2}
Hope this helps

4 0
4 years ago
Evaluate f(2) for the function f(x) = 3x² + 2x - 5.
Softa [21]

Answer:

f(2)= 11

Step-by-step explanation:

you have to substitute 2 for every x you see:

                       f(x) = 3x² + 2x - 5

                       f(2)= 3(2)^2+2(2)-5

                       f(2)= 11

6 0
3 years ago
Pls I need hlp with dis pls<br>very urgent ​
steposvetlana [31]

Answer:

ugh hard

Step-by-step explanation:

wow

8 0
3 years ago
Can someone help me with this one
HACTEHA [7]
X = 21 + 34
Answer: x = 55°
7 0
3 years ago
Need help (pic included)
ValentinkaMS [17]

Answer:

(-4,-2)

x=-4

y=-2

Step-by-step explanation:

-3x-4y=20

3(x-10y=16)=3x-30y=48

The reason I multiplied 3 to the second equation is for when we add the equations together the x will cancel out.

  -3x-4y=20

+  <u>3x-30y=48</u>

  -34y=68

Divide -34 from both sides.

y=-2

To find x you need to plug in -2 for y into one of the equations.

x-10y=16

x-10(-2)=16

Remember a negative times a negative equals a positive.

x+20=16

Subtract 20 from both sides.

x=-4

Hope this helps!

If not, I am sorry.

4 0
2 years ago
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