Answer:
One number, let's call it x, is 6 more than twice the other number, let's say this number is y.
x= 2y+6
x+y=21
We're left with a system of equations.
If we substitute the first equation in the second we find the value of y.
(2y+6)+y=21
3y+6=21
3y=15
<u><em>y=5</em></u>
Now that we have found the value of y, we can take that value and substitute it in the second equation (since it's easier) to find the value of x.
x+ (5)=21
<u><em>x=16</em></u>
<u><em>Now to check if our answers are correct, we plug in both values into any equation and see if they equate.</em></u>
x+y=21
(16)+(5)=21
21=21
Our solution is correct!
Answer:
1. x= 3y+6/2
y=2/3x-2
2.x=−y+3
y=−x+3
Step-by-step explanation:
1. Let's solve for x.
y=2/3x-2
Step 1: Flip the equation.
2/3x-2=y
Step 2: Add 2 to both sides.
2/3x-2+2=y+2
2/3x=y+2
Step 3: Divide both sides by 2/3.
2/3x/2/3=y+2/2/3
x= 3y+6/2
Let's solve for y.
y=2/3x-2
2. Let's solve for x.
y=−x+3
Step 1: Flip the equation.
−x+3=y
Step 2: Add -3 to both sides.
−x+3+−3=y+−3
−x=y−3
Step 3: Divide both sides by -1.
-x/-1=y-3/-1
x=−y+3
Let's solve for y.
y=−x+3
here are two graphs if you need a better explanation
HOPE THIS HELPS
Only the first one works
y = 3(-1)-2 = -5
y = -(0) -6 = -6 not -2
This is a substitution problem...
I'm sorry, all you did was say something. We need a question if you want an answer.
