Answer:
from the t-distribution table, at df = 7 and t = 2.23
Lies p-values [ 0.05 and 0.025 ]
Hence;
0.025 < p-value < 0.05
Step-by-step explanation:
Given that;
= 6.5 gpm
μ = 5 gpm
n = eight runs = 8
standard deviation σ = 1.9 gpm
Test statistics;
t = ( - μ) /
we substitute
t = (6.5 - 5) /
t = 1.5 / 0.67175
t = 2.23
the degree of freedom df = n-1 = 8 - 1
df = 7
Now, from the t-distribution table, at df = 7 and t = 2.23
Lies p-values [ 0.05 and 0.025 ]
Hence;
0.025 < p-value < 0.05
20 Cars on the bridge
60% of 20 = 12 Passenger Car
12×1.00=$12
20-12=8 Other Vehicles
8×2.75=$22
12+22=$34
So expected revenue is $34
$26.20 minimum cost of option 1
$36.68 minimum cost of option 2
Area₁ = Length x Width
A₁ = 80 x 36
A₁ = 2880 in² * this in only one side of the door.
Total Area = A₁ x 2 sides = 2880 = 5760 in² * only good for 1 coating of paint
Total Area to be coated = 5760 x 2 coats of paint = 11,520 in²
1st option - $10 / gallon and 4400 sq. in.
2nd option - $ 7 / gallon and 2200 sq. in
11,520 / 4400 = 2.62 x $10 = $26.20 minimum cost of option 1
11,520 / 2200 = 5.24 x $ 7 = $36.68 minimum cost of option 2
5.
Let x be the age of the father and y be the age of the son. As of today, he's 3 times older, so we have
10 years ago their ages were, respectively, x-10 and y-10, and the father was 5 times older:
So, we have the system
Using the first equation, we can substitute every occurrence of "x" with "3y" in the second equation:
So, the son is 20 years old, which means that the father is 60 years old.
Indeed, 10 years ago they were 10 and 50 years old, so the father was 5 times older.
6.
Let x be the age of the grandfather and y the age of the granddaughter. We know that the grandfather is 10 times older:
He also is 54 years older:
Again, if we substitute x=10y in the second equation we have