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Cloud [144]
3 years ago
7

The product of the roots of x2 + 6x - 55 = 0 is: -55 55

Mathematics
2 answers:
defon3 years ago
5 0

Answer:

- 55

Step-by-step explanation:

Given a quadratic equation in standard form : ax² + bx + c = 0 : a ≠ 0

The sum of the roots = - \frac{b}{a} and

The product of the roots = \frac{c}{a}

x² + 6x - 55 = 0 ← is in standard form

with a = 1, b = 6 and c = - 55, hence

product of the roots = \frac{-55}{1} = - 55

ira [324]3 years ago
5 0
Hey!
The answer is -55.
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Which domain restrictions apply to the rational expression?
andre [41]

Both expression have the same denominator: 9x²-1. Thus it must not be 0.

9x²-1=(3x-1)(3x+1)=0, resulting x=+-1/3.

Restrictions: x in R\{-1/3, 1/3}

Adding those expressions:

E=(-x-2)/(9x²-1 ) + (-5x+4)/(9x²-1)=

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3 years ago
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Lena [83]

Answer:

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3 years ago
(2x-7)^2 subtracted from 2
Zepler [3.9K]

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7 0
3 years ago
Please help this hurts
Svetllana [295]

Answer:

6x - 11y = -13 is the answer.

Step-by-step explanation:

Let's plug in the points to see what sticks.

Start with (-4, -1)

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2) 6x - 11y = 6(-4) - 11(-1) = -24 + 11 = -13

3) 6x - 7y = 6(-4) - 7(-1) = -24 + 7 = -17 \neq 17

4) 6x - 11y = 6(-4) - 11(-1) = -24 + 11 = -13 \neq 13

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2) 6x - 11y = 6(1.5) - 11(2) = 9 - 22 = -13

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3 years ago
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