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Cloud [144]
3 years ago
7

The product of the roots of x2 + 6x - 55 = 0 is: -55 55

Mathematics
2 answers:
defon3 years ago
5 0

Answer:

- 55

Step-by-step explanation:

Given a quadratic equation in standard form : ax² + bx + c = 0 : a ≠ 0

The sum of the roots = - \frac{b}{a} and

The product of the roots = \frac{c}{a}

x² + 6x - 55 = 0 ← is in standard form

with a = 1, b = 6 and c = - 55, hence

product of the roots = \frac{-55}{1} = - 55

ira [324]3 years ago
5 0
Hey!
The answer is -55.
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<em>since</em><em> </em><em>duration</em><em> </em><em>for</em><em> </em><em>return</em><em> </em><em>journey</em><em> </em><em>is</em><em> </em><em>from</em><em> </em><em>t</em><em>=</em><em>2</em><em>4</em><em> </em><em>mins</em><em> </em><em>to</em><em> </em><em>t</em><em> </em><em>mins</em><em>.</em>

\frac{4}{3}(t -24)= 28

\frac{4}{3}t - 32= 28

\frac{4}{3}t= 32 +28

\frac{4}{3}t= 60

t= 6 0\div  \frac{4}{3}

t= 45

*Here, I assume that this is a displacement- time graph, so the distance shown is the distance of the bus from the starting point because technically if it is a distance-time graph, the distance would still increase as the bus travels the 'return journey'.

Thus, distance is decreasing after t=24 and reaches zero at time= t mins so that is the return journey. (because when the bus returns back to starting point, displacement/ distance from starting point= 0km)

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