Answer:
About 432 people read at least one book per month.
Step-by-step explanation:
36/50 people read at least one book, multiply 36/50 by 12 to make the fraction 432/600.
B.) Hibiscus Street
The key thing to remember is the slope of the lines. The equation for a line in slope intercept form is
y = ax + b
where
a = slope
b = y intercept
So the equation for Oak Street is y = 2/3x - 7. So it's slope is 2/3. And any street that has the same slope will be given a tree name. And any street that's perpendicular will be given a flower name. You can determine is a line is perpendicular if it has a slope that's the negative reciprocal. So a street that's perpendicular to Oak street will have a slope of -3/2.
Now you've just been given the equation to a new street that's y = -3/2x - 2. Since the slope is -3/2 and Oak street has a slope of 2/3, the new street is perpendicular to Oak street. And given the naming scheme, that means that the new street will have the name of a flower. So let's look at the available street names and pick a flower.
<span>
A.) Weeping Willow Street
* Nope a Weeping Willow is a tree. So this name won't work.
B.) Hibiscus Street
* Yes. A Hibiscus is a flower, so this name is suitable.
C.) Oak Street
* Nope. Not only is this a tree instead of a flower, but there's already an Oak street. So bad choice.
D.) Panther Street
* Nope, this is an animal, not a flower. Bad choice.
</span>
Answer:
4x + 10
Step-by-step explanation:
I still cant see it sorry cant help without seeing it can you spell the question?
Answer:
His error is adding 10 and 2/3 before multiplying by a(age of the tree)
Step-by-step explanation:
The sum of 10 and two-thirds of that tree's age, in years, is equal to 50.
Correct equation
Sum = addition (+)
two-thirds = 2/3
The tree's age = a
10 + 2/3a = 50
2/3a = 50 - 10
2/3a = 40
a = 40 ÷ 2/3
= 40 × 3/2
= 60
a = 60 years
Javier writes the equation
(10 + two-thirds) a = 50
(10 + 2/3)a = 50
(30+2/3)a = 50
32/3a = 50
a = 50 ÷ 32/3
= 50 × 3/32
= 150/32
a = 150/32
His error is adding 10 and 2/3 before multiplying by a(age of the tree)
