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Cloud [144]
3 years ago
7

The product of the roots of x2 + 6x - 55 = 0 is: -55 55

Mathematics
2 answers:
defon3 years ago
5 0

Answer:

- 55

Step-by-step explanation:

Given a quadratic equation in standard form : ax² + bx + c = 0 : a ≠ 0

The sum of the roots = - \frac{b}{a} and

The product of the roots = \frac{c}{a}

x² + 6x - 55 = 0 ← is in standard form

with a = 1, b = 6 and c = - 55, hence

product of the roots = \frac{-55}{1} = - 55

ira [324]3 years ago
5 0
Hey!
The answer is -55.
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In ΔCDE, the measure of ∠E=90°, the measure of ∠D=23°, and EC = 1.3 feet. Find the length of DE to the nearest tenth of a foot.
BabaBlast [244]

Answer: length of DE is about 3.3 ft

Step-by-step explanation:  A calculator is necessary!

DE is the unknown hypotenuse of the triangle

get the sine of 23° = 0.3907311285

Use the equation for sine

<em>sin = o/h</em> .

To find h,  Substitute values for sin and o.  O is EC, Opposite the 23° angle D

<em>0.3907311285 = 1.3/h</em> multiply both sides by h

h(0.3907311285) = 1.3 divide both sides by 0.3907311285

h = 1.3/0.3907311285

3.327096065 = h, the length of the hypotenuse, DE.

7 0
2 years ago
F(x) = 2x^3 + 8
riadik2000 [5.3K]

Answer:32-10x

Step-by-step explanation:

7 0
3 years ago
Find the value of the variable y, where the sum of the fractions 6/(y+1) and y/(y-2) is equal to their product.
Blizzard [7]

Answer:

The answer is

y = 3

y =  - 4

Step-by-step explanation:

We must find a solution where

\frac{6}{y + 1}  +  \frac{y}{y - 2}  =  \frac{6}{y + 1}  \times  \frac{y}{y - 2}

Consider the Left Side:

First, to add fraction multiply each fraction on the left by it corresponding denomiator and we should get

\frac{6}{y + 1}  \times  \frac{y - 2}{y - 2}  +  \frac{y}{y - 2}  \times  \frac{y + 1}{y + 1}

Which equals

\frac{6y - 12}{(y -2) (y + 1)}  +  \frac{ {y}^{2} + y }{(y - 2)(y + 1)}

Add the fractions

\frac{y {}^{2} + 7y - 12 }{(y - 2)(y + 1)}  =  \frac{6}{y + 1}  \times  \frac{y}{y - 2}

Simplify the right side by multiplying the fraction

\frac{6y}{(y  + 1)(y + 2)}

Set both fractions equal to each other

\frac{6y}{(y + 1)(y - 2)}  =  \frac{ {y}^{2} + 7y - 12}{(y + 1)(y - 2)}

Since the denomiator are equal, we must set the numerator equal to each other

6y =  {y}^{2}  + 7y - 12

=  {y}^{2}  + y - 12

(y  + 4)(y - 3)

y =  - 4

y = 3

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3 years ago
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alexandr1967 [171]

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Step-by-step explanation:


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