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3 years ago

6 mm

Mathematics

1 answer:

Akimi4 [234]3 years ago

7 0

The answer is 20 ashsnenzhwnebdhdjsjdn

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The drama club sells hot drinks during intermission for the school play. At one performance they sold $200 worth of drinks. Kare

dsp73

Answer:

they sold 210 hot chocolates and 85 coffees

Step-by-step explanation:

We know that they sold $200 worth of drinks

x will be the number of hot chocolates sold

y will be the number of coffees sold

This means that

.75x+.5y=200

We also know that they sold 295 total drinks which means that

x+y=295

This is a system of linear equations which I will solve through substitution

x+y=295

Subtract y from both sides and divide by -1 to get

-x+295=y

Plug y into the first equation and get

.75x+.5(-x+295)=200

Distribute the .5 and simplify to get

.75x-.5x+147.5

.25x+147.5=200

Subtract 147.5 and then divide by .25 to get our x value

x=210

Now we can go back and plug this in into our equation

210+y=295

Subtract 210 to get y

y=85

This means that they sold 210 hot chocolates and 85 coffees

8 0

3 years ago

Sidney is making greeting cards, which she will sell by the box at an arts fair. She paid $32 for a booth at the fair, and the m

borishaifa [10]

So think of it like this she starts off $32 negative and subtract 3 from each box of cards she makes . So each box of cards she will make $8 that being said

32/8 =4 (it will take 4 box of cards to pay off her booth expense).

Sales would be 11x 4 =44

Expenditures would be 3x4 =32 (the amount used to make cards ) +32(the amount paid for the booth)

Which in total would be $64

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Cbegin%7Bequation%7D%5Ctext%20%7B%20Question%3A%20Find%20the%20value%20of%20%7D%20%5Cfrac%7B

ankoles [38]

$\bold{Heya!}$

Your answer to this is:

$\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}$

<h2>→ <u>EXPLANATION :-</u></h2>

<u />

<u /> $\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0} \: (1)$

$\sf{Apply \: rule:} \: (a) = a$

$\sf{(1) = 1$

$\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0} \: ^. \: 1$

$\sf{\frac{1}{1 \: + \:1} = \frac{1}{2}$

$\sf{\frac{2^1^0^0}{1 \: + \: x^2^0^0} ^.^ \: 1 \: = \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}$

$\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}$

Hopefully This Helps ! ~

#LearnWithBrainly

$\underline{Answer :}$

<em>Jaceysan ~</em>

7 0

2 years ago

Determine the domain of the function.

pav-90 [236]

$Domain \ of \ \frac{\sqrt{x + 3}}{(x + 8)(x - 2)}=(-3\leq x < 2) \cup (2 < x < \infty)$

i.e. x ≥ –3, x ≠ 2

4 0

3 years ago

Insert parentheses in the expression 6 + 10 x 2 so that the expression equals (12+1)*2

Lesechka [4]

6 + (10 x 2) = 26 = (12+1)*2

5 0

3 years ago