43 and 44, but it's closer to 43
Points of inflections are zeroes of the second derivative. We have:
So, the second derivative equals zero if and only if
So, this is the only point of inflection of this function.
Answer:
The second time when Luiza reaches a height of 1.2 m = 2 08 s
Step-by-step explanation:
Complete Question
Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.
H(t) = -0.6 cos (2pi/2.5)t + 1.5.
What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.
Solution
Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as
H(t) = -0.6cos(2π/2.5)t + 1.5
What is t when H = 1.2 m
1.2 = -0.6cos(2π/2.5)t + 1.5
0.6cos(2π/2.5)t = 1.2 - 1.5 = -0.3
Cos (2π/2.5)t = (0.3/0.6) = 0.5
Note that in radians,
Cos (π/3) = 0.5
This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,
Cos (5π/3) = 0.5
So,
Cos (2π/2.5)t = Cos (5π/3)
(2π/2.5)t = (5π/3)
(2/2.5) × t = (5/3)
t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.
Hope this Helps!!!
Answer: Yes, it is correct
Step-by-step explanation: Because of that, When you multiply 4.2 x 3 x 4 = 50.4
Circumference of the cylinder = 3.14 x 3.5 = 10.99 = 11 inches
so D. 11 x 14 is correct for the first part
area of the top = PI x r^2 = 3.14 x 1.75^2 = 9.62 inches
top and bottom = 9.62 x 2 = 19.23 = A. 19 inches
