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3 years ago

team rise over run finished the last 12 miles in 1/2 an hour what was their average speed in miles per hour

Mathematics

2 answers:

saveliy_v [14]3 years ago

4 0

Answer:

Step-by-step explanation: it’s been half an hour and they ran the 12 miles so in an hour which is double half an hour they ran two times what they did in half an hour

salantis [7]3 years ago

4 0

Answer:

Step-by-step explanation:

If you multiply 1/2 by 2 you get 1 and if you multiply 12 times 2 you get 24.

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3 years ago

class A has 13 pupils and class b has 28 pupils both classes sit the same maths test the mean score for class A is 23 the mean s

Wittaler [7]

Answer:

46.22

Step-by-step explanation:

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Clas B total= 57 x 28= 1596

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1 year ago

Help with simple interest rate P=$18,000, r= 7.5%, t=18 months

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3 years ago

PLEASE I need help on these 4 problems you don’t have to do them all but if you can at least do one of them TYSM

Brrunno [24]

Answer:

For right angle triangle,

we use Pythagoras theorem that is:

$c^{2} =a^{2} +b^{2}$

c = $\sqrt{a^{2} +b^{2} }$

For question 1:

c = ?

a = 40

b = 9

putting them in formula,

c = $\sqrt{40^{2} + 9^{2} }$

c = 41

For question 2:

c = ?

a = 12

b = 13

putting them in formula,

c = $\sqrt{12^{2} + 13^{2} }$

c = approximately 17.69181

For question 3:

c = 35

a = 20

b = ?

putting them in formula,

$c^{2} =a^{2} +b^{2}$

$35^{2} = 20^{2} + b^{2}$

1225 = 400 + $b^{2}$

$b^{2}$ = 1225 - 400

$b^{2}$ = 825

$\sqrt{b^{2} } = \sqrt{825}$

b = 5 $\sqrt{33}$

For question 4:

c = 37

a = 20

b = ?

putting them in formula,

$c^{2} =a^{2} +b^{2}$

$37^{2} = 20^{2} + b^{2}$

1369 = 400 + $b^{2}$

$b^{2}$ = 1369 - 400

$b^{2}$ = 969

Taking square root on both sides

b = 31.12

Hope it helps.

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2 years ago