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2 years ago

Solve for m.

Mathematics

1 answer:

Vilka [71]2 years ago

4 0

Answer:

m>-50

i asked for all the quizzes answers on my questions and i will tell you!

Step-by-step explanation:

k12

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Explain how to do (2^-2/3^3)^4 i need to know how to do this.

cricket20 [7]

Answer:

((2^(-2))÷(3^3))^4=

Step-by-step explanation: expand

5 0

2 years ago

Fill in the table using this function rule. y = 5x=+1

icang [17]

Answer:

x = 1; y = 6

x = 5; y = 26

x = 8; y = 41

x = 10; y = 51

Step-by-step explanation:

Just substitute the x values

4 0

2 years ago

An urn contains 5 white and 10 black balls. A fair die is rolled and that number of balls is randomly chosen from the urn. What

galina1969 [7]

Answer:

Part A:

The probability that all of the balls selected are white:

$P(A)=\frac{1}{6}(\frac{1}{3}+\frac{2}{21}+\frac{2}{91}+\frac{1}{273}+\frac{1}{3003}+0)\\ P(A)=\frac{5}{66}=0.075757576$

Part B:

The conditional probability that the die landed on 3 if all the balls selected are white:

$P(D_3|A)=\frac{\frac{2}{91}*\frac{1}{6}}{\frac{5}{66} } \\P(D_3|A)=\frac{22}{455}=0.0483516$

Step-by-step explanation:

A is the event all balls are white.

D_i is the dice outcome.

Sine the die is fair:

$P(D_i)=\frac{1}{6}$ for i∈{1,2,3,4,5,6}

In case of 10 black and 5 white balls:

$P(A|D_1)=\frac{5_{C}_1}{15_{C}_1} =\frac{5}{15}=\frac{1}{3}$

$P(A|D_2)=\frac{5_{C}_2}{15_{C}_2} =\frac{10}{105}=\frac{2}{21}$

$P(A|D_3)=\frac{5_{C}_3}{15_{C}_3} =\frac{10}{455}=\frac{2}{91}$

$P(A|D_4)=\frac{5_{C}_4}{15_{C}_4} =\frac{5}{1365}=\frac{1}{273}$

$P(A|D_5)=\frac{5_{C}_5}{15_{C}_5} =\frac{1}{3003}=\frac{1}{3003}$

$P(A|D_6)=\frac{5_{C}_6}{15_{C}_6} =0$

Part A:

The probability that all of the balls selected are white:

$P(A)=\sum^6_{i=1} P(A|D_i)P(D_i)$

$P(A)=\frac{1}{6}(\frac{1}{3}+\frac{2}{21}+\frac{2}{91}+\frac{1}{273}+\frac{1}{3003}+0)\\ P(A)=\frac{5}{66}=0.075757576$

Part B:

The conditional probability that the die landed on 3 if all the balls selected are white:

We have to find $P(D_3|A)$

The data required is calculated above:

$P(D_3|A)=\frac{P(A|D_3)P(D_3)}{P(A)}\\ P(D_3|A)=\frac{\frac{2}{91}*\frac{1}{6}}{\frac{5}{66} } \\P(D_3|A)=\frac{22}{455}=0.0483516$

7 0

2 years ago

A recipe requires ¾ cup of nuts for 1 batch of muffins. Write the number of batches of muffins that can be made using 7 ½ cups o

Ivahew [28]

Answer:

10 batches

Step-by-step explanation:

3/4 cups = 1 muffins

15/2 cups = x muffins

For x muffins,

3/4 × X = 15/2 × 1

3x × 2 = 15×4

6x = 60

Divide both sides by 6

6x/6 = 60/6

X = 10

Hence 10 batches of muffins will be made from 15/2 cups of nuts.

8 0

2 years ago

What is the <br> Number that the are talking about

anzhelika [568]

i can't comment so someone else is going to have to answer

but they need the whole page to answer this question.

4 0

3 years ago