-18(1) = -18,right?
4(3) = 12, right?
-18 - 12 = -30
From the looks of it, we had to "Subtract" the outcome of each problem that we went over
You're correct: -30 (option A.) would be your answer
<h3>I'll teach you how to solve (1/5x-4+2y)+(2/5x+5-4y)</h3>
-----------------------------------------------------------------
(1/5x-4+2y)+(2/5x+5-4y)
Remove parentheses:
1/5x-4+2y + 2/5x+5-4y
Group like terms:
1/5x+2/5x+2y-4y-4+5
Add similar elements:
3/5x+2y-4y-4+5
Add similar elements:
3/5x-2y-4+5
Multiply:
3x/5-2y-4+5
Add subtract the numbers:
3x/5+1-2y
Your Answer Is 3x/5+1-2y
plz mark me as brainliest :)
Answer:
3√r = k/s²
s²r^1/3 = k
Step-by-step explanation:
Cube root of r = 3√r
Square of s = s²
cube root of r varies inversely with the square of s
3√r = k/s²
Cross product
3√r * s² = k
s²r^1/3 = k
Note:
r^1/3
= 3√r
Answer:
B,C,E are right statements
Answer:
A
Step-by-step explanation:
So we have the equation:
First, let's subtract 16 from both sides:
Now, let's divide both sides by 3:
Remember that with fractional exponents, we can move the denominator into the root position. Therefore:
![(\sqrt[3]{x-4})^4=16](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7Bx-4%7D%29%5E4%3D16)
Let's take the fourth root of both sides. Since we're taking an even root, make sure to have the plus-minus symbol!
![\sqrt[3]{x-4} =\pm 2](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx-4%7D%20%3D%5Cpm%202)
Cube both sides. Since we're cubing, the plus-minus stays.
Add 4 to both sides.
Calculator:
So, our answer is A.
And we're done!
