1*n-10 = (5/6)*n-((1/3)*n)-7 // - (5/6)*n-((1/3)*n)-7
1*n-((5/6)*n)+(1/3)*n-10+7 = 0
n+(-5/6)*n+(1/3)*n-10+7 = 0
1/2*n-3 = 0 // + 3
1/2*n = 3 // : 1/2
n = 3/1/2
n = 6
That's just in case you had to show your work lol^^
Answer:
(x + 6, y + 0), 180° rotation, reflection over the x‐axis
Step-by-step explanation:
The answer can be found out simply , a trapezoid has its horizontal sides usually parallel meanwhile the vertical sides are not parallel.
The horizontal parallel sides are on the x-axis.
Reflection over y- axis would leave the trapezoid in a vertical position such that the trapezoid ABCD won't be carried on the transformed trapezoid as shown in figure.
So option 1 and 2 are removed.
Now, a 90 degree rotation would leave the trapezoid in a vertical position again so its not suitable again.
In,The final option (x + 6, y + 0), 180° rotation, reflection over the x‐axis, x+6 would allow the parallel sides to increase in value hence the trapezoid would increase in size,
180 degree rotation would leave the trapezoid in an opposite position and reflection over x-axis would bring it below the Original trapezoid. Hence, transformed trapezoid A`B`C`D` would carry original trapezoid ABCD onto itself
What is this question supposed to be?
If C= (-10, -9, -8, -7 ,-6 , -5) and D= ( -6, -5, -4, -3, -2, -1, ) , what is C n D ?
andrey2020 [161]
Answer:
C ∩ D = -5, -6
Step-by-step explanation:
Commons ones in both C and D are -5 and -6
The answer is x=3
if you divide each by -7 to isolate x, it’s equal to positive three because 2 negatives make a positive