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SOVA2 [1]
2 years ago
5

Write the Quadratic Formula

Mathematics
1 answer:
Evgen [1.6K]2 years ago
3 0

Answer:

y=x^2-4

Step-by-step explanation:

we know that

The function of the graph is a vertical parabola open upward

The vertex is a minimum

The equation of a vertical parabola in vertex form is equal to

y=a(x-h)^2+k

where

a is a coefficient

(h,k) is the vertex

In this problem

Looking at the graph

The vertex is the point (0,-4)

substitute

y=a(x-0)^2-4

y=ax^2-4

To determine the value of "a" take a point in the graph

I take the point (3,5)

substitute the value of x and the value of y and solve for a

5=a(3)^2-4\\9a=5+4\\9a=9\\a=1

therefore

The equation of the quadratic function is

y=x^2-4

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Step-by-step explanation:

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4)Comparing the given recursive formula a_{n}=a_{n-1}*-4

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5)Comparing the given recursive formula a_{n}=a_{n-1}*-4

with standard recursive formula a_{n}=a_{n-1}*r

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8th term= a_{1}*(r)^{n-1}=-4*(-4)^{7} =65536.

Explicit Formula =-4*(-4)^{n-1}

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with standard recursive formula a_{n}=a_{n-1}*r

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Explicit Formula =3*(-2)^{n-1}

7)Comparing the given recursive formula a_{n}=a_{n-1}*-5

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Explicit Formula =4*(-5)^{n-1}

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with standard recursive formula a_{n}=a_{n-1}*r

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8th term= a_{1}*(r)^{n-1}=2*(-5)^{7} =-156250.

Explicit Formula =2*(-5)^{n-1}

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