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4 years ago

Which two teachers received equivalent ratios of Apples from their total number of students?

Mathematics

1 answer:

Elenna [48]4 years ago

7 0

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Cones A and B both have volume 48(3.14) cubic units but they have different dimensions. Cone A has radius 6 units and height 4 u

OverLord2011 [107]

Part A r = $6\sqrt{2}$ units & h = 2 units:

Step-by-step explanation:

Here we have , cones A and B both have volume 48(3.14) cubic units but they have different dimensions. Cone A has radius 6 units and height 4 units. We need to find:

Part A

Find one possible radius and height for Cone B.

Since , volume of cone A and B are same so ,

Volume of cone A = $V_1$ , Volume of cone V = $V_2$

By hit & trial , One possible radius and height for Cone B is r = $6\sqrt{2}$ units & h = 2 units:

⇒ $V_2 = \frac{1}{3}\pi r^2h$

⇒ $V_2 = \frac{1}{3}(3.14) (6\sqrt{2})^2(2)$

⇒ $V_2 = 48units^3$

Part B

Explain how you know Cone B has the same volume as Cone A. 

Volume of cone A = $V_1$ :

Cone A has radius 6 units and height 4 units, So

⇒ $V_1 = \frac{1}{3}\pi r^2h$

⇒ $V_1 = \frac{1}{3}(3.14) (6})^2(4)$

⇒ $V_2 = 48units^3$

Volume of cone V = $V_2$

⇒ $V_2 = \frac{1}{3}\pi r^2h$

⇒ $V_2 = \frac{1}{3}(3.14) (6\sqrt{2})^2(2)$

⇒ $V_2 = 48units^3$

Hence, Volume of both are same!

4 0

3 years ago

Solve y=x³ with function y=fx

aalyn [17]

Answer:

Hope it will help you!!!!

4 0

3 years ago

Simplify (write without the absolute value sign) |x+3|, if x>2

kodGreya [7K]

Answer:

Step-by-step explanation

Note that if x>2, then x+3>3+2=5. Then x+3>0. Recall that the absolute value function is defined as

$|x|=x \text{ if } x\geq 0$

$|x|=-x \text{ if } x< 0$

Since x+3>0, we have that |x+3|=x+3

6 0

3 years ago

Find the slope that passes through (4,9) and (6,8)

Aliun [14]

Answer: Y=-1/2x +11

-1/2 is the slope and 11 is the y-intercept

3 0

3 years ago

What is the equation of the line that passes through the point (-2,-1) and has a slope of 5/2

Darya [45]

Answer:

y = (5/2)x + 4

Step-by-step explanation:

We'll look for an equation in the format y = mx + b, where mn is the slope and b the y-intercept (the value of y when x = 0).

y = mx + b

m is (5/2)

y = (5/2)x + b

We need a value of b that will force the line through point (-2,-1). Enter the point (-2,-1) in the equation and solve for b:

y = (5/2)x + b

-1 = (5/2)(-2) + b

-1 = -5 + b

b = 4

The equation is y = (5/2)x + 4

See attached image.

5 0

2 years ago