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4 years ago

Which two teachers received equivalent ratios of Apples from their total number of students?

Mathematics

1 answer:

Elenna [48]4 years ago

7 0

^^^^^^^^^^^^^^^^^^^^^^

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Rectangle B is a scale drawing of rectangle A using a scale factor of 150%. The area of rectangle A is 32 square units. What is

drek231 [11]

Answer:

The answer is 72 square units

Step-by-step explanation:

If rectangle A is scaled by 150% that means the length and breadth of rectangle A were both increased by 1.5(150%) to yield rectangle B.

So, the area of rectangle B is 1.5L x 1.5B = 2.25LB

But, LB = area of rectangle A which is = 32

So, area of rectangle B

= 2.25 x 32

= 72square units.

5 0

3 years ago

Read 2 more answers

I need help with this question please help.<br> Its gt geometry

Savatey [412]

Answer: First one is 140, second one is 70

Step-by-step explanation: They’re corresponding angles

7 0

3 years ago

10 people who build at the same rate can frame a house in 6 days. What fractional part of a house can 4 people frame a house in

Alina [70]

10 people who build at the same rate can frame a house in 6 days. That means it will take one person $10\times6=60$ days to finish the house.

Which means that it will take 4 people $\frac{60}{4}=15$ days to finish the house.

So, the fractional part of the house 4 people can frame in 3 days will be $\frac{3}{15}=\frac{1}{5}$

Thus, Option D is the correct answer.

8 0

3 years ago

Plss answer!! <br>MERRY Christmas!!! <br>Critical Question. AAAAA

liberstina [14]

Answer:

Step-by-step explanation:

abc = 1

We have to prove that,

$\frac{1}{1+a+b^{-1}}+\frac{1}{1+b+c^{-1}}+\frac{1}{1+c+a^{-1}}=1$

We take left hand side of the given equation and solve it,

$\frac{1}{1+a+\frac{1}{b}}+\frac{1}{1+b+\frac{1}{c}}+\frac{1}{1+c+\frac{1}{a}}$

Since, abc = 1,

$\frac{1}{c}=ab$ and c = $\frac{1}{ab}$

By substituting these values in the expression,

$\frac{1}{1+a+\frac{1}{b}}+\frac{1}{1+b+\frac{1}{c}}+\frac{1}{1+c+\frac{1}{a}}=\frac{1}{1+a+\frac{1}{b}}+\frac{1}{1+b+ab}+\frac{1}{1+\frac{1}{ab}+\frac{1}{a}}$

$=\frac{b}{b+ab+1}+\frac{1}{1+b+ab}+\frac{ab}{ab+1+b}$

$=\frac{1+b+ab}{1+b+ab}$

$=1$

Which equal to the right hand side of the equation.

Hence, $\frac{1}{1+a+b^{-1}}+\frac{1}{1+b+c^{-1}}+\frac{1}{1+c+a^{-1}}=1$

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3 years ago

I really need help on my geometry homework!!!!! PLEASE HELP ME!!!!

otez555 [7]

the 10th questions answer is aaa congruence

3 0

3 years ago