Answer: When you divide by 100 you are essentially moving the decimal of the number two places to the left. In undoing this you would have to move the decimal of the number two places to the right.
28.003 would then turn into 2,800.3
Step-by-step explanation:
Unfortunately I cannot draw a chart on here but that is the best I can do.
Answer:
See below
Step-by-step explanation:
<u>Given function</u>
<u>We can find its factors:</u>
- x³ + 3x² - 7x - 21 =
- x²(x + 3) - 7(x + 3) =
- (x² - 7)(x + 3)
We can conclude that the given polynomial function is fully divisible by (x + 3) and the quotient is (x² - 7)
Also one of zeros of the function is -3
Answer:
x = c - b
Step-by-step explanation:
c = x + b
Subtract b on both sides,
c - b = x + b - b
c - b = x
x = c - b
Hence, solved.
Answer:
Herman needs to buy 3 sticker packs to have a total of 100 stickers.
Explanation:
33 x 3 = 99
99 + 1 = 100
Answer: The square root of π has attracted attention for almost as long as π itself. When you’re an ancient Greek mathematician studying circles and squares and playing with straightedges and compasses, it’s natural to try to find a circle and a square that have the same area. If you start with the circle and try to find the square, that’s called squaring the circle. If your circle has radius r=1, then its area is πr2 = π, so a square with side-length s has the same area as your circle if s2 = π, that is, if s = sqrt(π). It’s well-known that squaring the circle is impossible in the sense that, if you use the classic Greek tools in the classic Greek manner, you can’t construct a square whose side-length is sqrt(π) (even though you can approximate it as closely as you like); see David Richeson’s new book listed in the References for lots more details about this. But what’s less well-known is that there are (at least!) two other places in mathematics where the square root of π crops up: an infinite product that on its surface makes no sense, and a calculus problem that you can use a surface to solve.
Step-by-step explanation: this is the same paragraph The square root of π has attracted attention for almost as long as π itself. When you’re an ancient Greek mathematician studying circles and squares and playing with straightedges and compasses, it’s natural to try to find a circle and a square that have the same area. If you start with the circle and try to find the square, that’s called squaring the circle. If your circle has radius r=1, then its area is πr2 = π, so a square with side-length s has the same area as your circle if s2 = π, that is, if s = sqrt(π). It’s well-known that squaring the circle is impossible in the sense that, if you use the classic Greek tools in the classic Greek manner, you can’t construct a square whose side-length is sqrt(π) (even though you can approximate it as closely as you like); see David Richeson’s new book listed in the References for lots more details about this. But what’s less well-known is that there are (at least!) two other places in mathematics where the square root of π crops up: an infinite product that on its surface makes no sense, and a calculus problem that you can use a surface to solve.
