1+tan^2(A) = sec^2(A) [Pythagorean Identities]
tan^2(A)cot(A) = tan(A)[tan(A)cot(A)] = tan(A)[1] = tan(A)
*see photo for complete solution*
Answer:
22.5 miles per hour
Step-by-step explanation:
<u>Given system of equations</u>
5(s-w)=900
4(s+w)=900
<u />
<u>Set equations equal to each other</u>
5(s-w)=4(s+w)
5s-5w=4s+4w
s-5w=4w
s=9w
<u>Solve for w using the substitution s=9w</u>
4(s+w)=900
4(9w+w)=900
4(10w)=900
40w=900
w=22.5
Therefore, the speed of the wind is 22.5 miles per hour
Answer:
y = 1/2x + 1.
Step-by-step explanation:
Use the point-slope form of a straight line:
y - y1 = m(x - x1) (where m=slope and(x1,y1) is a point on line).
y - 3 = 1/2(x - 4)
y = 1/2x - 2 + 3
y = 1/2x + 1.
Answer:
Step-by-step explanation:
A = P(1+r/n)^ nt
A = 2000(1+.04/2)^(5*2)
A =
= $2437.99
-7-w<10
Add 7 to each side
-w<17
Change signs and flip sign
w>17
Hope this helps :)