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madam [21]
3 years ago
14

How do you solve this math problem?

Mathematics
2 answers:
navik [9.2K]3 years ago
6 0
You just do 1/1 then multiply that by 7 which would be 7/7. Then do 7/7 - 3/7 which would be 4/7 (which can not be simplified)
Valentin [98]3 years ago
4 0
7/7 = to 1 whole and has the same denominator as 4/7 so 7/7 minus 4/7 is equal to 3/7
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An athletic field is a 48 yd​-by-96 yd ​rectangle, with a semicircle at each of the short sides. A running track 20 yd wide surr
MA_775_DIABLO [31]

The distance would be equal to 2 times the longest side of the rectangle plus twice the shortest side multiplied by pi / 2 for the semicircle, that is:

longest side 96 and shortest 48

D = 2 * (96) + 2 * (1/2) * pi * 48

D = 192 + pi * 48

This shorter side, which starts at 48, will expand each time by two more in proportion to 20 of the running track between 8 than the number of divisions, that is, 2 * (20/8) = 5

In other words, there are 8 distances, like this:

D1 = 192 + 3.14 * 48 = 342.72 yd

D2 = 192 + 3.14 * (48 + 5) = 358.42 yd

D3 = 192 + 3.14 * (48 + 10) = 374.12 yd

D4 = 192 + 3.14 * (48 + 15) = 389.82 yd

D5 = 192 + 3.14 * (48 + 20) = 405.52 yd

D6 = 192 + 3.14 * (48 + 25) = 421.22 yd

D7 = 192 + 3.14 * (48 + 30) = 436.92 yd

D8 = 192 + 3.14 * (48 + 35) = 452.62 yd

6 0
2 years ago
#26 7s=4 please help
const2013 [10]
7s = 4
/7.    /7 


s= 4/7

thats the equation right?
7 0
3 years ago
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Alex787 [66]

Answer:

B

Step-by-step explanation:

easy

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Answer:

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The side length is the square root of the area, so is ...

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4 0
3 years ago
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