Answer:
the linear equation is :
y= -2625x+5737875
and 440000 employees will be in year 2271
Step-by-step explanation:
in order to find the linerar equation let us first convert the given data into (x,y ) co-ordinates i.e
x1= 1987 y1= 522,000
and
x2= 2003, y2 = 480000
according to two point form:

In this example we have x1=1987 , y1=522000 , x2=2003 and y2=480000. So,

now to find the year when there will be 440000 employs working , we simply put y= 440000 in the above derived equation

Between the square roots of 7 and 8, because e^2 is equal to around 7.4, which is between 7 & 8. I hope this helps!
Isolate one variable in the system of equations. Use substitution to create a one-variable equation. Then, set the quadratic equation equal to zero and find the discriminant. If the discriminant is negative, then there are no real number solutions. If the discriminant is zero, then there is one real number solution. If the discriminant is positive, then there are two real number solutions.
The answer to the question is d.
$140(.075) = 10.5
10.5+140= 150.50
the total would be $150.50