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lbvjy [14]
3 years ago
13

I need help with this problem plzzz

Mathematics
1 answer:
Effectus [21]3 years ago
6 0

Not sure sorry but you can. Try searching on google or yahoo answers

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Jasmine purchases a tablet computer for $233.56. Apps for the tablet cost 99¢ each. If Jasmine had $279 to spend on the tablet a
Leto [7]
45 games i just used a calculator will u please mark me brainiest hope this helps :)
7 0
3 years ago
CAN I ALSO GET AN EXPLANATION PLEASE!​
ddd [48]

Answer:

ok no prob ...........lolllllll

7 0
3 years ago
Sylvia, John, and Peter invested their savings in a bank. The ratio of the investment of Sylvia's to John's is 1: 3 and that of
Nastasia [14]

Answer:

4 : 12 : 15

Step-by-step explanation:

S : J = 1 : 3

J : P= 4 : 5

Using John's ratio to find a common ratio for all

S : J

(1 : 3)4 = 4 : 12

J : P

(4 : 5)3 = 12 : 15

Therefore our ratio is

S : J : P

4 : 12 : 15

3 0
3 years ago
Q is the midpoint for the points S(11, -6) and T(-1, 10). Find the length of segment QT.<br> QT=
iris [78.8K]

Answer:

10

Step-by-step explanation:

QT=ST/2=√(12^2+16^2)/2=10

3 0
3 years ago
What are the real zeroes of x3 + 6 x2 – 9x - 54?
o-na [289]

Answer:

Option B 3,-3,-6 is correct.

Step-by-step explanation:

We need to find real zeroes of x^3+6x^2-9x-54

Solving

x^3+6x^2-9x-54\\=(x^3+6x^2)+(-9x-54)

Taking x^2 common from first 2 terms and -9 from last two terms we get

=(x^3+6x^2)+(-9x-54)\\=x^2(x+6)-9(x+6)\\

Taking (x+6) common

(x+6)(x^2-9)\\

x^2-9 can be solved using formula a^2-b^2 = (a+b)(a-b)

=(x+6)((x)^2-(3)^2)\\=(x+6)(x+3)(x-3)

Putting it equal to zero,

(x+6)(x+3)(x-3) =0\\x+6 =0, x+3=0\,\, and\,\, x-3=0\\x=-6, x=-3\,\, and\,\,  x=3

So, Option B 3,-3,-6 is correct.

7 0
3 years ago
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