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shutvik [7]
3 years ago
6

Use the data below to construct a stem and leaf display on your own paper. Determine if the determination form the book, Last Co

wboys by Connie Brooks (University of New Mexico Press), cowboys were by and large from good families and not necessarily young to die. They were not mostly drunkards, gun gunslingers, or thieves as portrayed in the movies. Does your stem and leaf display of the data support that finding? (answer yes or no).
Cowboys: Longevity How long did real cowboys live? One answer may be found in the book The Last Cowboys by Connie Brooks (Univeristy of New Mexico Press). This delightgul book represents a thoughtful sociological study of cowboys in West Texas and Southeastern New Mexico around the year 1890. A sample of 32 cowboys gave the following years of longevity:
Mathematics
1 answer:
AveGali [126]3 years ago
7 0
Given that a sample of 32 cowboys gave the following years of longevity: 58 52 68 86 72 66 97 89 84 91 91 92 66 68 87 86 73 61 70 75 72 73 85 84 90 57 77 76 84 93 58 47

The stem and leaf display for the data is given as follows:
4   |   7
5   |   2, 7, 8, 8
6   |   1, 6, 6, 8, 8
7   |   0, 2, 2, 3, 3, 5, 6, 7
8   |   4, 4, 4, 5, 6, 6, 7, 9
9   |   0, 1, 1, 2, 3, 7
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Factorise 54 and 36 using prime factorization..<br><br>No spam<br>No irrelevant answers​
KiRa [710]

Refer to the attachment!

4 0
3 years ago
Read 2 more answers
10. 5(3-9b) = 3(-15b – 2)
olga2289 [7]

Answer:

No Solution

Explanation:

5(3 - 9b) = 3(-15b – 2)

Expand

5(3 - 9b): 15 - 45b

3(-15b - 2): -45b - 6

15 - 45b = -45b - 6

Subtract 5 From Both Sides

15 - 45b - 15 = -45b - 6 - 15

Simplify

-45b = -45b - 21

Add 15b To Both Sides

-45b + 15b = -45b - 21 + 15b

Simplify

0 = -21

No Solution

8 0
3 years ago
What is the value of x in the equation 40(x - 3) = 24x - 48?
pogonyaev

Answer:

x=10.5

Step-by-step explanation:

40x-120=24x-48

40x-168=24x

16x-168=0

16x=168

x=10.5

Have a great day!

6 0
2 years ago
Solve for x.<br> (1/3) over 3 =x over 8
Ugo [173]

8/3=3x (cross multiplied to get this)

X=8/9 (divided both sides by 3)

Hope this helps :)

8 0
3 years ago
Read 2 more answers
A local car dealer claims that 25% of all cars in San Francisco are blue. You take a random sample of 600 cars in San Francisco
sammy [17]

Answer:

No, we can't reject the dealer's claim with a significance level of 0.05.

Step-by-step explanation:

We are given that a local car dealer claims that 25% of all cars in San Francisco are blue.

You take a random sample of 600 cars in San Francisco and find that 141 are blue.

<u><em>Let p = proportion of all cars in San Francisco who are blue</em></u>

SO, Null Hypothesis, H_0 : p = 25%   {means that 25% of all cars in San Francisco are blue}

Alternate Hypothesis, H_A : p \neq 25%   {means that % of all cars in San Francisco who are blue is different from 25%}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                  T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = sample proportion of 600 cars in San Francisco who are blue =   \frac{141}{600} = 0.235

            n = sample of cars = 600

So, <u><em>test statistics</em></u>  =  \frac{0.235-0.25}{{\sqrt{\frac{0.235(1-0.235)}{600} } } } }

                               =  -0.866

<em>Now at 0.05 significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics lies within the range of critical values of z so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.</em>

Therefore, we conclude that 25% of all cars in San Francisco are blue which means the dealer's claim was correct.

4 0
3 years ago
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